Haryana State Board HBSE 7th Class Maths Solutions Chapter 2 Fractions and Decimals Ex 2.5 Textbook Exercise Questions and Answers.
Haryana Board 7th Class Maths Solutions Chapter 2 Fractions and Decimals Exercise 2.5
Question 1.
What is greater ?
(i) 0.5 or 0.05
(ii) 0.7 or 0.5
(iii) 7 or 0.7
(iv) 1.37 or 1.49
(v) 2.03 or 2.30
(vi) 0.8 or 0.88.
Solution:
(i) 0.5 > 0.05 [Because 5 > 0]
(ii) 0.7 > 0.5 [Because .7 > .5]
(iii) 7 > 0.7
(iv) 1.49 > 1.37 [Because 4 > 3]
(v) 2.30 > 2.03 [Because 3 > 0]
(vi) 0.88 > 0.80. [Because 8 > 0]
Question 2.
Express as rupees using decimals.
(i) 7paise
(ii) 7 rupees 7paise
(iii) 77 rupees 77paise
(iv) 50paise
(v) 235paise.
Solution:
(i) ∵ 100 paise = 1 Rupee
∴ paise = 0.07 Rupees
(ii) 7 rupees 7 paise = 7.07 Rupees.
(iii) 77 rupees 77 paise = 77.77 Rupees.
(iv) 50 paise = 0.50 Rupees
(v) 235 paise = \(\frac{235}{100}\)
Rupees = 2.35 Rupees.
Question 3.
(i) Express 5 cm in metre and kilometre.
(ii) Express 35 mm in cm, m and km.
Solution:
(i) ∵ 100 cm = 1 m and 1000 m
= 1 km
5 cm = 0.05 m and \(\frac{0.05}{1000}\) = 0.00005 km
(ii) 35 mm – 3.5 cm = \(\frac{3.5}{100}\) = 0.035 m = \(\frac{0.035}{1000}\)
= 0.000035 km
Question 4.
Express in kg.
(i) 200g
(ii) 3470g
(iii) 4 kg 8 g
(iv) 2598 mg
Solution:
(i) ∵ 1000 gm = 1 kg
200g = \(\frac{200}{1000}=\frac{2}{10}\) = 0.2kg
(ii) 3470 g = \(\frac{3470}{1000}=\frac{347}{100}\) = 3.47 kg
(iii) 4 kg 8g = 4.008 kg
(iv) 2598 mg = \(\frac{2508}{1000}\)
= \(\frac{2598}{1000 \times 1000} \mathrm{~kg}=\frac{2598}{1000000} \mathrm{~kg}\) = 0.02598 kg
Question 5.
Write the following decimal numbers in the expanded form :
(i) 20.03
(ii) 2.03
(iii) 200.03
(iv) 2.034
Solution:
(i) 20.03 = 2 x 10 + 0 x 1 + 0 x (\(\frac{1}{10}\)) + 3 x (\(\frac{1}{100}\))
(ii) 2.03 = 2 x 1 + 0 x (\(\frac{1}{10}\)) + 3 x (\(\frac{1}{100}\))
(iii) 200.03 = 2 x 100 + 0 x 10 + 0 x 1 + 0 x (\(\frac{1}{10}\)) + 3 x (\(\frac{1}{100}\)) + 4 x (\(\frac{1}{1000}\))
Question 6.
Write the place value of 2 in the following decimal numbers :
(i) 2.56
(ii) 21.37
(iii) 10.25
(iv) 9.42
(v) 63.352.
Solution:
(i) 2.56 Place value of 2 = Ones
(ii) 21.37 Place value of 2 = Tens
(iii) 10.25 Place value of 2 = Tenths
(iv) 9.42 Place value of 2 = Hundredths
(v) 63.352 Place value of 2 = Thousandths.
Question 7.
Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is
12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much ?
Solution:
Total travelled distance of Dinesh = 7.5 km + 12.7 km = 20.2 km
Total travelled distance of Ayub = 9.3 km + 11.8 km = 21.1 km
or, 21.1 km – 20.2 km = 0.9 km
∴ Ayub travelled 0.9 km more.
Question 8.
Shyama bought 5 kg 300g apples and 3 kg 250g mangoes. Sarala bought 4 kg 800g apples and 4 kg 150g bananas. Who bought more fruits ?
Solution:
or, 8.950 kg – 8.550 kg = 0.400 kg
.’. Sarala bought 400 g more fruits.
Question 9.
How much less is 28 km than 42.6 km?
Solution:
