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Haryana State Board HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 7 Fractions Exercise 7.6

Question 1.
(a) Solve :

Solution:

Question 2.
Sarita bought \(\frac{2}{5}\) m of ribbon and Lalita \(\frac{3}{4}\) m of ribbon. What was the total length of the ribbon they bought ?
Solution:
Ribbon bought by Sarita = \(\frac{2}{5}\) m
Ribbon bought by Lalita = \(\frac{3}{4}\) m
Total length of ribbon = \(\frac{2}{5}+\frac{3}{4}=\frac{2 \times 4+3 \times 5}{20}\)
= \(\frac{8+15}{20}=\frac{23}{20}=1 \frac{3}{20} \mathrm{~m}\)

Question 3.
Naina was given 1\(\frac{1}{2}\) piece of cake and Najma was given 1\(\frac{1}{3}\) piece of cake.
Find the total amount of cake given to both of them.
Solution:
Cake given to Naina = 1\(\frac{1}{2}\) = \(\frac{3}{2}\)
Cake giveen to Najma = 1\(\frac{1}{3}\) = \(\frac{4}{3}\)
∴ Total amount of cake given to both of them
= \(\frac{3}{2}+\frac{4}{3}=\frac{3 \times 3+2 \times 4}{6}\)
= \(\frac{9+8}{6}=\frac{17}{6}=2 \frac{5}{6}\)

Question 4.
Fill in the boxes:

Solution:

Question 5.
Complete the addition, subtraction box.

Solution:

Question 6.
A piece of wire 7/8 metre long broke into two pieces. One piece was 1/4 metre long. How long is the other piece ?
Solution:
Total length of a piece of wire = \(\frac{7}{8}\) m
Length of one piece = \(\frac{1}{4}\) m
∴ Length of the other piece = \(\frac{7}{8}-\frac{1}{4}=\frac{7-2}{8}=\frac{5}{8}\)m

Question 7.
Nandni’s house is \(\frac{9}{10}\) km. from her school. She walked some distance and then took a bus for \(\frac{1}{2}\) km upto the school. How far did she walk ?
Solution:
Total distance between house and school = \(\frac{9}{10}\) km
Distance covered by bus = \(\frac{1}{2}\) km
∴ Distance walked by her = \(\frac{9}{10}-\frac{1}{2}=\frac{9-5}{10}\)
= \(\frac{4}{10}=\frac{2}{5}\) km.

Question 8.
Asha and Samuel have bookshelves of the same size. Asha’s shelf is \(\frac{5}{6}\) full of books and Samuel’s shelf is \(\frac{2}{5}\) full. Whose bookshelf is more full ? By what fraction?
Answer:
Asha’s shelf is \(\frac{5}{6}\) full of books,
Samuel’s shelf is \(\frac{2}{5}\) full of books
Now, \(\frac{5}{6}-\frac{2}{5}=\frac{5 \times 5-2 \times 6}{30}=\frac{25-12}{30}=\frac{13}{30}\)
∴ Asha’s bookshelf is more full by \(\frac{13}{30}\) fraction.

Question 9.
Jaydev takes 2\(\frac{1}{5}\) minutes to walk across the school ground. Rahul takes \(\frac{7}{4}\) minutes to do the same. Who takes less time and by what fraction ?
Solution:
Time taken by Jaydev to walk across the school ground = \(2 \frac{1}{5}=\frac{11}{5}\) minutes
Time taken by Rahul to do the same = \(\frac{7}{4}\) minutes
Now, \(\frac{11}{5}-\frac{7}{4}=\frac{11 \times 4-5 \times 7}{20}=\frac{44-35}{20}=\frac{9}{20}\)
∴ Rahul takes less time by \(\frac{9}{20}\) fraction.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 7 Fractions Exercise 7.3

Question 1.
Write the fractions. Are all these fractions equivalent ?

Solution:
(a) \(\frac{1}{2}, \frac{2}{4}, \frac{3}{6}, \frac{4}{8}\). All these fractions are equivalent.
(b) ,\(\frac{4}{12}, \frac{3}{9}, \frac{2}{6}, \frac{1}{3}, \frac{6}{15}\). First four fractions are equivalent. All fractions are not equivalent. 14 a bo 15

Question 2.
Write the fractions and pair up the equivalent fraction from each row A and B.

Solution:

Question 3.
Replace in each of the following by the correct number:

Solution:

Question 4.
Find the equivalent fraction of \(\frac{3}{5}\) having
(a) denominator 20
(b) numarator 9
(c) denominator 30
(d) numarator 27
Solution:

Question 5.
Find the equivalent fraction of \(\frac{36}{48}\) with
(a) numarator 9
(b) denominator 4
Solution:

Question 6.
Check whether the given fractions are equivalent :
(a) \(\frac{5}{9}, \frac{30}{54}\)
(b) \(\frac{3}{10}, \frac{12}{50}\)
(c) \(\frac{7}{13}, \frac{5}{11}\)
Solution:

Question 7.
Reduce the following fractions to their simplest forms :
(a) \(\frac{48}{60}\)
(b) \(\frac{150}{60}\)
(c) \(\frac{84}{98}\)
(d) \(\frac{12}{52}\)
(e) \(\frac{7}{28}\)
Solution:

Question 8.
Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils, and Jamaal used up 40 pencils. What fraction did each use up ? Check if each has used up an equal fraction of their pencils ?
Solution:
∵ Ramesh had 20 pencils and he used up 10 pencils.
Fraction of pencils used by Ramesh = \(\frac{10}{20}=\frac{1}{2}\)
∵ Sheelu had 50 pencils and she used up 25 pencils.
∴ Fraction of pencils used by Sheelu = \(\frac{25}{50}=\frac{1}{2}\)
∵ Jamaal had 80 pencils and he used up 40 pencils.
∴ Fraction of pencils used up by Jamaal = \(\frac{40}{80}=\frac{1}{2}\)
Yes, each had used up an equal fraction of their pencils.

Question 9.
Match the equivalent fractions and write other 2 for each :

Solution:
Solution:
To reduce \(\frac{250}{400}\) we find the H .C.F. of 250 and 400.
We have

∴ 250 = 2 x 5 x 5 x 5
and 400 = 2 x 2 x 2 x 2 x 5 x 5
∴ H.C.F. of 250 and 400
= 2 x 5 x 5 = 50
\(\frac{250}{400}=\frac{250 \div 50}{400 \div 50}=\frac{5}{8}\)
Thus (i) is matched to (d).

(ii) To reduce \(\frac{180}{200}\) we find the HCF of 180 and 200.
We have

∴ 180 = 2 x 2 x 3 x 3 x 5
and 200 = 2 x 2 x 2 x 5 x 5
∴ HCF of 180 and 200
= 2 x 2 x 5 = 20
\(\frac{180}{200}=\frac{180 \div 20}{200 \div 20}=\frac{9}{10}\)
Thus, (ii) is matched to (e).

(iii) To reduce \(\frac{660}{990}\), we find the HCF of
660 and 990.
We have

∴ 660 = 2 x 2 x 3 x 5 x 11
and 990 = 2 x 3 x 3 x 5 x 11
∴ HCF of 660 and 990
= 2 x 3 x 5 x 11 = 330
\(\frac{660}{990}=\frac{660 \div 330}{990 \div 330}=\frac{2}{3}\)
Thus, (iii) is matched to (a).

(iv) To reduce \(\frac{180}{360}\), we find the HCF of 180 and 360.
∴ 180 = 180
360 = 180 x 2
∴ HCF of 180 and 360 = 180
\(\)
Thus, (iv) is matched to (c).

(v) To reduce \(\frac{220}{550}\), we find the HCF of 220
and 550 We have
220 = 550
and 220 = 2 x 110
HCF of 220 and 550 = 110
\(\)
Thus, (v) is matched to (b).

Haryana State Board HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.2 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 7 Fractions Exercise 7.2

Question 1.
Draw number lines and place the points on them.

Solution:

Question 2.
Express the following as mixed fractions :

Solution:

Question 3.
Express the following as improper fractions:

Solution:

Haryana State Board HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.1 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 7 Fractions Exercise 7.1

Question 1.
Give the fraction representing the shaded partion?

Solution:

Question 2.
Colour the part according to the fraction given

Solution:

Question 3.
Identify the error, if any ?

Solution:
(i) This is not \(\frac{1}{2}\), because the two parts are not equal.
(ii) This is not \(\frac{1}{4}\) , because the four parts are not equal.
(iii) This is not \(\frac{3}{4}\), because the four parts are not equal.

Question 4.
What fraction of a day is 8 hours ?
Solution:
∵ A day has 24 hours
∴ 8 hours = \(\frac{8}{24}=\frac{1}{3}\)

Question 5.
What fraction of an hour is 40 minutes ?
Solution:
∵ An hour has 60 minutes
∴ 40 minutes = \(\frac{40}{60}=\frac{2}{3}\)

Question 6.
Arya, Abhimanyu and Vivek share for lunch. Arya brought two sandwiches, one made of vegetable and one of jam. The other two boys forget theirs lunch. Arya agree to share his sandwiches so that each person will have an equal shares of each sandwich.
(a) How can Arya divide his sandwiches so that each person has an equal share ?
(b) What part of a sandwich will each boy receive ?
Solution:
(a) Arya can divide each sandwich into three equal parts, total 6 parts.
(b) Each boy will receive l/3rd part of each sandwich i.e. each gets 2 parts.

Question 7.
Kanchan has three frocks that she wears while playing. The material is good, but the colours are faded. Her mother buys same blue dye and uses it on two of the frocks. What fraction of Kanchan’s playing frocks did her mother dye ?
Solution:
Her mother dyed 2/3rd of Kanchan’s playing frocks.

Question 8.
Write the natural numbers from numbers ?
Solution:

Prime numbers are : 2, 3, 5, 7, 11 i.e., 5.
Hence, \(\frac{5}{11}\) fraction are prime numbers.

Question 9.
Write the natural numbers from 102 to 103 numbers ? What fraction of them are prime numbers?
Solution:

Prime numbers are : 103, 107, 109, 113 i.e., 4
Total natural numbers are 12.
Hence, \(\frac{4}{12}=\frac{1}{3}\) fraction are prime numbers.

Question 10.
What fraction of these circles have X’s in them ?

Solution:
(a) \(\frac{5}{8}\)
(b) \(\frac{3}{8}\)
(c) \(\frac{4}{8}\)

Question 11.
Dinesh, Sumit, Ram, Joy, Marshal, Imran, Jayant, Babu, Kabir and Rohan decide to play basketball. The first five boys are of one team and the rest are of the other team.
(a) What fraction of the boys is of the first team ?
(b) What, does this fraction mean ? Are equal parts involved ? If so, equal in what sense?
Solution:
(a) ∵ There are ten boys in all. and no. of boys in the first team = 5
∴ Fraction of the boys in the first team
= \(\frac{5}{10}=\frac{1}{2}\)

(b) Fraction \(\frac{1}{2}\) means that half the boys are in the first team. Yes, equal parts are involved.
This shows that five boys are in the first team and five boys are in the second team.

Question 12.
Kristin receive a C.D. Player for her birthday. She has been collecting C.D’s since then. She bought 3 C.D’s and received 5 others as gifts. What fraction of her total C.D’s did she buy ?
Solution:
Total number of C.D’s she has = 3 + 5 = 8
Number of C.D’s bought by her = 3
Hence, the required fraction of C.D’s she bought
= \(\frac{3}{8}\)

Haryana State Board HBSE 6th Class Maths Solutions Chapter 6 Integers InText Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 6 Integers InText Questions

Try These (Page 148)

Question 1.
Write the following numbers with appropriate signs :
(a) 100 m below sea level (b) 25°C above 0° temperature
(c) 15°C below 0° temperature (d) 5 number less than 0.
Solution:
(a) +100 m, (b) +25°C, (c) -15°C, (d) -5.

Try These (Page 151)

Question 1.
Mark -3, 7, -4, -8,1 and -5 on the number line. Can you tell which is the largest integer amongst these integers ?
Solution:

7 is the largest integer amongst these integers.

Try These (Page 152)

Question 1.
Compare the following pairs of numbers using > or < :

From the above exercise, we arrived at the following conclusions, give examples of each :
(a) Every positive integer is larger than every negative integer.
e.g. 3 > – 1, 5 > -2, 6 > -3 etc.
(b) Zero is less than every positive integer.
e.g. 0 < 2, 0 < 5, 0 < 10 etc.
(c) Zero is larger than every negative integer.
e.g. 0 > -3, 0 > -7, 0 > -15 etc.
(d) Zero is neither a negative integer nor a positive integer.
(e) Farther a number from zero on the right, larger is its value.
e.g. 7 > 5, 8 > 3, 10 > 2 etc.
(f) Farther a number from zero on the left, smaller is its value.
e.g. -5 < -3, -7. < -4, -10 < -6 etc.

Try These (Page 159)

Find the answers of the following additions:

Question 1.
(a) (-11)+ (-12)
(b) (+10) + (+4)
(c) (-32)+ (-25)
(d) (+23) + (+40).
Solution:
(a) (-11) + (-12) = -23
(b) (+10) + (+4) =+14
(c) (-32) + (-25) = -57
(d) (+23) + (+40) = +63.

Try These (Page 160)

Question 1.
Find the solution of the following :
(a) (-7) + (+8)
(b) (-9) + (+13)
(c) (+7) + (-10)
(d) (+12) + (-7).
Solution:
(a) (-7) + (+8) = +1
(b) (-9) + (+13) = +4
(c) (+7) + (-10) = -3
(d) (+12) + (-7) = +5.

Try These (Page 162)

Question 1.
Find the solution of the following additions using a number line :
(a) (-2) + 6
(b) (-6) + 2
Make two such questions and solve them using the number line.
Solution:
(a)

First we move 2 steps to the left of 0 reaching -2 and then from this point we move 6 steps to the right. We reach the point 4. Thus, (-2) + (+6) = 4.

(b)

First we move 6 steps to the left of 0 reaching -6 and then from this point we move 2 steps to the right. We reach the point -4. Thus, (-6) + (+2) = -4.

Question 2.
Find the solution of the following additions using a number line :
(i) (-4) + (+3)
(ii) (+4) + (-3)
Solution:
(i)

First we move 4 steps to the right of 0 reaching 4 and then from this point we move 3 steps to the right. We reach the point -1. Thus, (-4) + (+3) = -1.

(ii)

First we move 4 steps to the right of 0 reaching 4 and then from this point we move 3 steps to the left. We reach the point 1. Thus, (+4) + (-3) = 1.

Question 3.
Find the solution of the following without using a number line :
(a) (+7) + (-11), (b) (-13) + (+10), (c) (-7) + (+9), (d) (+10) + (-5).
Make five such questions and solve them.
Solution:
(a) (+7) + (-11) = -4,
(b) (-13) + (+10) = -3,
(c) (-7) + (+9) = +2,
(d) (+10) + (-5) = 5.

Question 4.
Find the solution of the following without using a number line :
(i) (+5) + (+3),
(ii) (-6) +(-2),
(iii) (-5)+(+15),
(iv) (-8) + (+5),
(v) (+7) + (+10).
Solution:
(i) (+5) + (+3) = +8,
(ii) (-6) + (-2) = -8,
(iii) (-5) + (+15) = + 10
(iv) (-8) + (+5) = -3,
(v) (+7) + (+10) = 17.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 6 Integers Ex 6.3 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 6 Integers Exercise 6.3

Question 1.
Subtract:
(a) 35 – (20)
(b) 72 – (90)
(c) (-15) – (-18)
(d) (-20)-(13)
(e) 23 – (-12)
(f) (-32) – (-40)
Solution:
(a) 35 – (20) = 15.
(b) 72-(90) = -18.
(c) (-15) – (-18) = (-15) + 18 = 3.
(d) (-20) – 13 = -33.
(e) 23-(-12) = 23 + 12 = 35.
(f) (-32) – (-40) = (-32) + 40 = 8.

Question 2.
Fill in the blanks with >, < or = sign :
(a) (-3) + (-6) ……………. (-3) – (-6)
(b) (-21) – (-10) ……………. (-31) + (-11)
(c) 45-(-11) ……………. 57 +(-4)
(d.) (-25) -(-42) ……………. (-42) – (-25).
Solution:
(a) (-3) + (-6) = -9
and (-3)-(-6) = (-3) + 6 = 3
∵ (-9) < 3
∴ (-3) + (-6) < (-3) – (-6)

(b) (-21) – (-10) = -21 + 10 = -11
and (-31) + (-11) = – 42
∵ (-11) > (-42)
∴ (-21) – (-10) > (-31) + (-11)

(c) 45 – (-11) = 45+ 11 = 56
and 57 + (-4) = 53
56 > 53
∴ 45 – (-11) > 57 + (-4)

(d) (-25) – (-42) = (-25) + 42 = 17
and (-42) – (-25) = -42 + 25 = -17,
∵ 17 > -17
∴ (-25) – (-42) > (-42) – (-25).

Question 3.
Fill in the blanks :
(a) (-8) + = 0
(b) 13 + = 0
(c) 12 +(-12) =
(d) (-4) + =-12
(e) – 15 = – 10.
Solution:
(a) (-8) + 8 = 0
(b) 13 + (-13) = 0
(c) 12 + (-12) = 0
(d) (-4) + (-8) = -12
(e) 5 + (-15) = -10.

Question 4.
Find the value of:
(a) (-7)-8-(-25)
(b) (-13) + 32-8-1
(c) (-7) + (-8) + (-90)
(d) 50 – (-40) – (-2).
Solution:
(a) (-7) – 8 – (-25) = -7-8 + 25 = -15 + 25 = 10
(b) (-13) + 32 – 8 – 1 = 32 – 13 – 8 – 1
= 32 – 22 = 10
(c) (-7) + (-8) + (-90) = -7 – 8 – 90 = -105
(d) 50 – (-40) – (-2) = 50 + 40 + 2 = 92.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 6 Integers Ex 6.2 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 6 Integers Exercise 6.2

Question 1.
Using the number line, write the integer which is :
(a) 3 more than 5
(b) 5 more than -5
(c) 6 less than 2
(d) 3 less than -2.
Solution:
(a) We want to find the integer which is 3 more than 5. So we start from 5 and proce 3 steps to the right of 5 to reach 8 as shown below. (Fig.)
∴ 3 more than 5 is 8.

(b) We want to find an integer which is 5 more than -5. So we start from -5 and proi 5 steps to the right of-5 to reach 0 as shown below (Fig.).

∴ 5 more than -5 is 0.

(c) We want to find an integer which is 6 less than 2. So we start from 2 and move 6 steps to the left of 2 to reach -4 as shown in Fig. , ∴ 6 less than 2 is -4.

(d) We want to find an integer is 3 less than -2. So we start from -2 and move 3 steps to the left to reach-5 as shown in Fig. 6.13.
∴ 3 less than -2 is -5.

Question 2.
Use a number line and add the following integers :
(a) 9 + (-6)
(b) 5 + (-11)
(c) (-1) + (-7)
(d) (-5) + 10
(e) (-1) + (-2) + (-3)
(f) (-2) + 8 + (-4).
Solution:
(a) 9 + (—6) = 3

(b) 5 + (-11) = -6

(c) (-1) + (-7) = -8

(d) (-5) + 10 = 5

(e) (-1) + (-2) + (-3) = -6

(f) (-2) + 8 + (-4). or 8 + (-2) + (-4) = 8 + (-6) = 2

Question 3.
Add without using a number line:
(a) 11 + (-7)
(b) (-13) + 18
(c) (-10) + (+19)
(d) (-250) + (+150)
(e) (-380) + (-270)
(f) (-217) + (-100).
Solution:
(a) 11 + (-7) = 4
(b) (-13) + 18 = 5
(c) (-10) + (+19) = 9
(d) (-250) + (+150) = -100
(e) (-380) + (-270) = -650
(f) (-217) + (-100) = -317.

Question 4.
Find the sum of:
(a) 137 and -354
(b) -52 and 52
(c) -312 , 39 and 192
(d) -50, -200 and 300.
Solution:
(a) 137 + (-354) = -217
(b) (-52) + (52) = 0,
(c) (-312) + 39 + 192 = (-312) + 231 = -81,
(d) (-50) + (-200) + 300 = (-250) + 300 = 50.

Question 5.
Find the value of:
(а) (-7) + (-9) + 4 + 16
(b) (37) + (-2) + (-65) + (-8).
Solution:
(a) (-7) + (-9) + 4 + 16 = (-16) + 20 = 4.
(b) (37) + (-2) + (-65) + (-8) =
37 + (-2 – 65 – 8) = 37 + (-75) = -38.
Note : Additive Inverse : Numbers such as 3 and -3, 2 and -2, added to each other give the sum zero. They are called additive inverse of each other.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 6 Integers Ex 6.1 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 6 Integers Exercise 6.1

Question 1.
Write opposites of the following :
(a) Increase in weight
(b) 30 km north
(c) 326 BC
(d) Loss of Rs. 700
(e) 100 m above sea level.
Solution:
(a) Decrease in weight,
(b) 30 km south,
(c) 326 AD,
(d) Gain of Rs. 700,
(e) 100 m below sea level.

Question 2.
Represent the following numbers as integers with appropriate signs :
(a) An aeroplane is flying at a height of two thousand metres above the ground.
(b) A sub-marine is moving at a depth of eight hundred, metres below the sea level.
(c) A deposit of Rs. two hundred.
(d) Withdrawal of Rs. seven hundred.
Solution:
(a) +2000,
(b) -800,
(c) +200,
(d) -700.

Question 3.
Represent the following numbers on a number line :
(a) +5 (b) -10 (c) +8 (d) -1 (e) -6.
Solution:

Question 4.
Adjacent is a vertical line, representing integers. Observe it and locate the following points :
(a) If point D is +8, then which point, is -8 ?
(b) Is point. G a negative integer or a positive integer ?
(c) Which is the point, opposite to H ?
(d) Write integers for points B and E.
(e) Which point, marked on this number line has the least, value, if) Arrange all the points in decreasing order of value.
Solution:
(a) F,
(b) negative integer,
(c) A,
(d) +4, -10,
(e) E,
(f) D, C, B, A, O, H, G, F, E.

Question 5.
Following is the list of temperatures of five places in India, on a particular day of the year.

(a) Write the temperatures of these places in the form of integers in the blank column.
(b) Following is the number line representing the temperature in degree Celsius.

Plot the name of the city against its temperature.
(c) Which is the coolest place ?
(d) Write the names of the places whose temperatures are above 10°C.
Solution:
(a) -10°C, -2°C, +30°C, + 20°C, -5°C
(b)

(c) Siachin is the coolest place.
(d) Delhi and Ahmedabad.

Question 6.
In each of the following pairs, which number is to the right of the other on the number line ?
(a) 2, 9,
(b) -3, -8,
(c) 0, -1,
(d) -11, 10,
(e) -6, 6,
(f) 1, -100.
Solution:
(a) 9, (b) -3, (c) 0, (d) 10, (e) 6, (f) 1.

Question 7.
Write all the integers between the given pairs (write them in the increasing order).
(a) 0 and -7
(b) -4 and 4-
(c) -S and -15
(d) -30 and -23.
Solution:
(a) -6,-5,-4,-3,-2,-1.
(b) -3, -2, -1, 0, 1, 2, 3.
(c) -14, -13, -12, -11, -10, -9.
(d) -29, -28, -27, -26, -25, -24.

Question 8.
(a) Write four negative integers greater than -20.
(b) Write four negative integers less than -10.
Solution:
(a) -19, -18, -17, -16, (b) —11, -12, -13, -14.

Question 9.
For the following statements, write true (T) or false (F). If the statement is false, correct the statement.
(a) -8 is to the right of-10 on a number line.
(b) -100 is to the right of -50 on a number line.
(c) Smallest negative number is -1.
(d) -26 is larger than -25.
Solution:
(a) T,
(b) F, -100 is to the left of -50 on the number line,
(c) F, there is no smallest negative number,
(d) F, -26 is smaller than -25.

Question 10.
Draw a number line and answer the following :
(a) Which number will we reach if we move 4 numbers to the right of -2 ?
(b) Which number will we reach if w,e move 5 numbers to the left of 1 ?
(c) If we are at -8 on the number line, in which direction should we move to reach -13 ?
(d) If we are at -6 on the number dine, in which direction should we move to reach -1 ?

Solution:
(a) 2,
(b) -4,
(c) left,
(d) right.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 5 Understanding Elementary Shapes InText Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 5 Understanding Elementary Shapes InText Questions

Try These (Page 110)

Question 1.
Take post card. Use divider to measure its two adjacent sides.
Solution:
Open the divider. Place the end point of one of its arms at A and the second end point at B.
Without disturbing the opening, lift the divider and place it pn the ruler. Ensure that one end point is at the zero mark of the ruler. Now read the mark against the other end point. Similarly, measure its breadth BC.

Question 2.
Select any three objects having a flat top. Measure all the sides of the top using a divider and a ruler.
Solution:
(i) Open the divider. Place the end point of one of its arms at A and the second end point at B. Without disturbing the opening, lift the divider and place it on the ruler. Ensure that one end point is at the zero mark of the ruler. Now read the mark against the other end point. Similarly measure its breadth BC.
(ii) We can measure length and breadth of a playing card in the same way as above.
(iii) Similarly, we can measure the three sides of a triangular sheet ABC.

Try These (Page 114)

Question 1.
What is the angle name for half a revolution ? ‘
Solution:
The name of the angle for half a revolution is straight angle.

Question 2.
What is the angle name for one fourth revolution ?
Solution:
The name of the angle for one fourth revolution is right angle.

Question 3.
Draw 5 other situations of one fourth, half and three fourth revolution on a clock.
Solution:

Note : There is no special name for three fourth of a revolution.

Try These (Page 116-117)

Question 1.
The clock moves from 12 to 5. Is the revolution of the hour- hand more than 1 right angle ? [Fig.]
Solution:
Yes, the revolution of the hour-hand is more than 1 right angle.

Question 2.
What does the angle look like ? The clock moves 5 to 9. Is the angle moved by hour-hand more than 1 right angle ? [Fig.]
Solution:
The angle looks like obtuse angle.
Yes, the angle moved by hour hand is more than 1 right angle.

Question 3.
Draw the following and check the angle with your RA tester.
(a) going from 12 to 2, (b) from 6 to 7, (c) from 4 to 8, (d) from 2 to 5.
Solution:

Haryana State Board HBSE 6th Class Maths Solutions Chapter 5 Understanding Elementary Shapes Ex 5.4 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 5 Understanding Elementary Shapes Exercise 5.4

Question 1.
What is the measure of (i) a right angle, (ii) a straight angle ?
Solution:
(i) The measure of a right angle is 90°.
(ii) The measure of a straight angle is 180°.

Question 2.
Say True or False :
(a) The measure of an acute angle < 90°.
(b) The measure of an obtuse angle < 90°.
(c) The measure of a reflex angle > 180°.
(d) The measure of one complete revolution = 360°.
(e) If m ∠A = 530 and m ∠B 35°, then m∠A > m ∠B.
Solution:
(a) True,
(b) False,
(c) True,
(d) True,
(e) True.

Question 3.
Write down the measures of:
(a) some acute angles.
(b) some obtuse angles.
(Give two examples of each).
Solution:
(a) 30° and 60° are acute angles.
(b) 110° and 120° are obtuse angles.

Question 4.
Measure the angles given below, using the Protractor and write down the measure.

Solution:
(a) 45°,
(b) 125°,
(c) 90°,
(d) ∠1 = 40°, ∠2 = 125°, ∠3 = 95°.

Question 5.
Which angle has a large measure ?

First estimate and then measure. Measure of Angle A =
Measure of Angle B =
Solution:
Measure of ∠A = 40° and measure of ∠B = 65°
∴ ∠B > ∠A.

Question 6.
From these two angles, which has a larger measure ? Estimate and then confirm by measuring them.

Solution:
∠A = 45° and ∠B = 60°
∴ ∠B > ∠A.

Question 7.
Fill in the blanks with acute, obtuse, right or straight :
(a) An angle whose measure is less than that of a right angle is ………………
(b) An angle whose measure is greater than that of a right angle is ………………
(c) An angle whose measure is the sum of the measures of two right angles is ………………
(d) When the sum of the measures of two angles is that of a right angle, then each one of them is ………………
(e) When the sum of the measures of two angles is that of a straight angle, one of them should be ……………… or ………………
Solution:
(a) acute,
(b) obtuse,
(c) straight,
(d) acute,
(e) acute, obtuse.

Question 8.
Find the measure of the angle shown in each figure. (First estimate with your eye and then find the actual measure with a protractor).

Solution:
(a) 40°, (b) 65°, (c) 130°, (d) 135°.

Question 9.
Find the angle measure between the hands of the clock in each figure :

Solution:
(a) 90°, (b) 30°, (d) 180°.

Question 10.
Investigate : In the given figures, protractor shows 30° Look at the same figure through a magnifying glass. Does the angle becomes larger ? Does the size of the angle change ?

Solution:
No, No.

Question 11.
Measure and classify each angle.

Solution: