HBSE 6th Class Maths Solutions Chapter 6 Integers Ex 6.2

Haryana State Board HBSE 6th Class Maths Solutions Chapter 6 Integers Ex 6.2 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 6 Integers Exercise 6.2

Question 1.
Using the number line, write the integer which is :
(a) 3 more than 5
(b) 5 more than -5
(c) 6 less than 2
(d) 3 less than -2.
Solution:
(a) We want to find the integer which is 3 more than 5. So we start from 5 and proce 3 steps to the right of 5 to reach 8 as shown below. (Fig.)
∴ 3 more than 5 is 8.

(b) We want to find an integer which is 5 more than -5. So we start from -5 and proi 5 steps to the right of-5 to reach 0 as shown below (Fig.).

∴ 5 more than -5 is 0.

(c) We want to find an integer which is 6 less than 2. So we start from 2 and move 6 steps to the left of 2 to reach -4 as shown in Fig. , ∴ 6 less than 2 is -4.

(d) We want to find an integer is 3 less than -2. So we start from -2 and move 3 steps to the left to reach-5 as shown in Fig. 6.13.
∴ 3 less than -2 is -5.

Question 2.
Use a number line and add the following integers :
(a) 9 + (-6)
(b) 5 + (-11)
(c) (-1) + (-7)
(d) (-5) + 10
(e) (-1) + (-2) + (-3)
(f) (-2) + 8 + (-4).
Solution:
(a) 9 + (—6) = 3

(b) 5 + (-11) = -6

(c) (-1) + (-7) = -8

(d) (-5) + 10 = 5

(e) (-1) + (-2) + (-3) = -6

(f) (-2) + 8 + (-4). or 8 + (-2) + (-4) = 8 + (-6) = 2

Question 3.
Add without using a number line:
(a) 11 + (-7)
(b) (-13) + 18
(c) (-10) + (+19)
(d) (-250) + (+150)
(e) (-380) + (-270)
(f) (-217) + (-100).
Solution:
(a) 11 + (-7) = 4
(b) (-13) + 18 = 5
(c) (-10) + (+19) = 9
(d) (-250) + (+150) = -100
(e) (-380) + (-270) = -650
(f) (-217) + (-100) = -317.

Question 4.
Find the sum of:
(a) 137 and -354
(b) -52 and 52
(c) -312 , 39 and 192
(d) -50, -200 and 300.
Solution:
(a) 137 + (-354) = -217
(b) (-52) + (52) = 0,
(c) (-312) + 39 + 192 = (-312) + 231 = -81,
(d) (-50) + (-200) + 300 = (-250) + 300 = 50.

Question 5.
Find the value of:
(а) (-7) + (-9) + 4 + 16
(b) (37) + (-2) + (-65) + (-8).
Solution:
(a) (-7) + (-9) + 4 + 16 = (-16) + 20 = 4.
(b) (37) + (-2) + (-65) + (-8) =
37 + (-2 – 65 – 8) = 37 + (-75) = -38.
Note : Additive Inverse : Numbers such as 3 and -3, 2 and -2, added to each other give the sum zero. They are called additive inverse of each other.