HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3

Haryana State Board HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 7 Fractions Exercise 7.3

Question 1.
Write the fractions. Are all these fractions equivalent ?
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 1
Solution:
(a) \(\frac{1}{2}, \frac{2}{4}, \frac{3}{6}, \frac{4}{8}\). All these fractions are equivalent.
(b) ,\(\frac{4}{12}, \frac{3}{9}, \frac{2}{6}, \frac{1}{3}, \frac{6}{15}\). First four fractions are equivalent. All fractions are not equivalent. 14 a bo 15

Question 2.
Write the fractions and pair up the equivalent fraction from each row A and B.
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 2
Solution:
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 3
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 4

HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3

Question 3.
Replace in each of the following by the correct number:
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 5
Solution:
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 6

Question 4.
Find the equivalent fraction of \(\frac{3}{5}\) having
(a) denominator 20
(b) numarator 9
(c) denominator 30
(d) numarator 27
Solution:
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 7
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 8

Question 5.
Find the equivalent fraction of \(\frac{36}{48}\) with
(a) numarator 9
(b) denominator 4
Solution:
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 9

HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3

Question 6.
Check whether the given fractions are equivalent :
(a) \(\frac{5}{9}, \frac{30}{54}\)
(b) \(\frac{3}{10}, \frac{12}{50}\)
(c) \(\frac{7}{13}, \frac{5}{11}\)
Solution:
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 10

Question 7.
Reduce the following fractions to their simplest forms :
(a) \(\frac{48}{60}\)
(b) \(\frac{150}{60}\)
(c) \(\frac{84}{98}\)
(d) \(\frac{12}{52}\)
(e) \(\frac{7}{28}\)
Solution:
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 11
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 12

HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3

Question 8.
Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils, and Jamaal used up 40 pencils. What fraction did each use up ? Check if each has used up an equal fraction of their pencils ?
Solution:
∵ Ramesh had 20 pencils and he used up 10 pencils.
Fraction of pencils used by Ramesh = \(\frac{10}{20}=\frac{1}{2}\)
∵ Sheelu had 50 pencils and she used up 25 pencils.
∴ Fraction of pencils used by Sheelu = \(\frac{25}{50}=\frac{1}{2}\)
∵ Jamaal had 80 pencils and he used up 40 pencils.
∴ Fraction of pencils used up by Jamaal = \(\frac{40}{80}=\frac{1}{2}\)
Yes, each had used up an equal fraction of their pencils.

Question 9.
Match the equivalent fractions and write other 2 for each :
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 13
Solution:
Solution:
To reduce \(\frac{250}{400}\) we find the H .C.F. of 250 and 400.
We have
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 14
∴ 250 = 2 x 5 x 5 x 5
and 400 = 2 x 2 x 2 x 2 x 5 x 5
∴ H.C.F. of 250 and 400
= 2 x 5 x 5 = 50
\(\frac{250}{400}=\frac{250 \div 50}{400 \div 50}=\frac{5}{8}\)
Thus (i) is matched to (d).

(ii) To reduce \(\frac{180}{200}\) we find the HCF of 180 and 200.
We have
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 15
∴ 180 = 2 x 2 x 3 x 3 x 5
and 200 = 2 x 2 x 2 x 5 x 5
∴ HCF of 180 and 200
= 2 x 2 x 5 = 20
\(\frac{180}{200}=\frac{180 \div 20}{200 \div 20}=\frac{9}{10}\)
Thus, (ii) is matched to (e).

HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3

(iii) To reduce \(\frac{660}{990}\), we find the HCF of
660 and 990.
We have
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3 16
∴ 660 = 2 x 2 x 3 x 5 x 11
and 990 = 2 x 3 x 3 x 5 x 11
∴ HCF of 660 and 990
= 2 x 3 x 5 x 11 = 330
\(\frac{660}{990}=\frac{660 \div 330}{990 \div 330}=\frac{2}{3}\)
Thus, (iii) is matched to (a).

(iv) To reduce \(\frac{180}{360}\), we find the HCF of 180 and 360.
∴ 180 = 180
360 = 180 x 2
∴ HCF of 180 and 360 = 180
\(\)
Thus, (iv) is matched to (c).

HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.3

(v) To reduce \(\frac{220}{550}\), we find the HCF of 220
and 550 We have
220 = 550
and 220 = 2 x 110
HCF of 220 and 550 = 110
\(\)
Thus, (v) is matched to (b).

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