Haryana State Board HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.5 Textbook Exercise Questions and Answers.
Haryana Board 6th Class Maths Solutions Chapter 7 Fractions Exercise 7.5
Question 1.
Write these fractions appropriately as additions or subractions:
Solution:
Question 2.
Complete the statements given with each figure.
Solution:
Question 3.
Solution:
Question 4.
Shubham painted 2/3 of the wall space in his room. His sister Madhavi helped and painted 1/3 of the wall space. How much did they paint together ?
Solution:
Shubham painted 2/3 of the wall space in his room.
Madhavi painted 1/3 of the wall space.
∴ The part they painted together = \(\frac{2}{3}+\frac{1}{3}=\frac{2+1}{3}=\frac{3}{3}\) = 1
Hence, they painted the complete wall.
Question 5.
Kamlesh bought 3\(\frac{1}{2}\) kg of sugar whereas Anwar bought 2\(\frac{1}{2}\) kg of sugar. Find the total amount of sugar bought by both of them.
Answer:
Amount of sugar bought by Kamlesh
= 3\(\frac{1}{2}\)kg
Amount of sugar bought by Anwar
= 2\(\frac{1}{2}\)kg
Total amount of sugar bought by both of them
= \(3 \frac{1}{2}+2 \frac{1}{2}=\frac{7}{2}+\frac{5}{2}[/atex]
= [latex]\frac{7+5}{2}=\frac{12}{2}\) = 6 kg
Question 6.
Fill in the missing fractions :
Solution:
Question 7.
The teacher taught 3/5 of the book. Mahesh revised 1/5 more on his own. How much does he still have to revise ?
Solution:
Teacher taught \(\frac{3}{5}\) of the book.
Mahesh revised \(\frac{1}{5}\) more on his own.
∴ Total part of the book revised by Mahesh
\(\frac{3}{5}+\frac{1}{5}=\frac{3+1}{5}=\frac{4}{5}\)
∴ He still have to revise
= \(1-\frac{4}{5}=\frac{5-4}{5}=\frac{1}{5}\)
Question 8.
Javed was given 5/7 of a bucket of oranges. What fraction of oranges was left in the basket ?
Solution:
∴ Javed was given \(\frac{5}{7}\)of oranges.
∵ Fraction of oranges left in the basket
= \(1-\frac{5}{7}=\frac{7-5}{7}=\frac{2}{7}\)