HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6

Haryana State Board HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 7 Fractions Exercise 7.6

Question 1.
(a) Solve :
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6 1
Solution:
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6 2
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6 3
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6 4

HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6

Question 2.
Sarita bought \(\frac{2}{5}\) m of ribbon and Lalita \(\frac{3}{4}\) m of ribbon. What was the total length of the ribbon they bought ?
Solution:
Ribbon bought by Sarita = \(\frac{2}{5}\) m
Ribbon bought by Lalita = \(\frac{3}{4}\) m
Total length of ribbon = \(\frac{2}{5}+\frac{3}{4}=\frac{2 \times 4+3 \times 5}{20}\)
= \(\frac{8+15}{20}=\frac{23}{20}=1 \frac{3}{20} \mathrm{~m}\)

Question 3.
Naina was given 1\(\frac{1}{2}\) piece of cake and Najma was given 1\(\frac{1}{3}\) piece of cake.
Find the total amount of cake given to both of them.
Solution:
Cake given to Naina = 1\(\frac{1}{2}\) = \(\frac{3}{2}\)
Cake giveen to Najma = 1\(\frac{1}{3}\) = \(\frac{4}{3}\)
∴ Total amount of cake given to both of them
= \(\frac{3}{2}+\frac{4}{3}=\frac{3 \times 3+2 \times 4}{6}\)
= \(\frac{9+8}{6}=\frac{17}{6}=2 \frac{5}{6}\)

Question 4.
Fill in the boxes:
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6 5
Solution:
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6 6

Question 5.
Complete the addition, subtraction box.
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6 7
Solution:
HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6 8

HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6

Question 6.
A piece of wire 7/8 metre long broke into two pieces. One piece was 1/4 metre long. How long is the other piece ?
Solution:
Total length of a piece of wire = \(\frac{7}{8}\) m
Length of one piece = \(\frac{1}{4}\) m
∴ Length of the other piece = \(\frac{7}{8}-\frac{1}{4}=\frac{7-2}{8}=\frac{5}{8}\)m

Question 7.
Nandni’s house is \(\frac{9}{10}\) km. from her school. She walked some distance and then took a bus for \(\frac{1}{2}\) km upto the school. How far did she walk ?
Solution:
Total distance between house and school = \(\frac{9}{10}\) km
Distance covered by bus = \(\frac{1}{2}\) km
∴ Distance walked by her = \(\frac{9}{10}-\frac{1}{2}=\frac{9-5}{10}\)
= \(\frac{4}{10}=\frac{2}{5}\) km.

Question 8.
Asha and Samuel have bookshelves of the same size. Asha’s shelf is \(\frac{5}{6}\) full of books and Samuel’s shelf is \(\frac{2}{5}\) full. Whose bookshelf is more full ? By what fraction?
Answer:
Asha’s shelf is \(\frac{5}{6}\) full of books,
Samuel’s shelf is \(\frac{2}{5}\) full of books
Now, \(\frac{5}{6}-\frac{2}{5}=\frac{5 \times 5-2 \times 6}{30}=\frac{25-12}{30}=\frac{13}{30}\)
∴ Asha’s bookshelf is more full by \(\frac{13}{30}\) fraction.

HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6

Question 9.
Jaydev takes 2\(\frac{1}{5}\) minutes to walk across the school ground. Rahul takes \(\frac{7}{4}\) minutes to do the same. Who takes less time and by what fraction ?
Solution:
Time taken by Jaydev to walk across the school ground = \(2 \frac{1}{5}=\frac{11}{5}\) minutes
Time taken by Rahul to do the same = \(\frac{7}{4}\) minutes
Now, \(\frac{11}{5}-\frac{7}{4}=\frac{11 \times 4-5 \times 7}{20}=\frac{44-35}{20}=\frac{9}{20}\)
∴ Rahul takes less time by \(\frac{9}{20}\) fraction.

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