Haryana State Board HBSE 6th Class Maths Solutions Chapter 7 Fractions Ex 7.6 Textbook Exercise Questions and Answers.

## Haryana Board 6th Class Maths Solutions Chapter 7 Fractions Exercise 7.6

Question 1.

(a) Solve :

Solution:

Question 2.

Sarita bought \(\frac{2}{5}\) m of ribbon and Lalita \(\frac{3}{4}\) m of ribbon. What was the total length of the ribbon they bought ?

Solution:

Ribbon bought by Sarita = \(\frac{2}{5}\) m

Ribbon bought by Lalita = \(\frac{3}{4}\) m

Total length of ribbon = \(\frac{2}{5}+\frac{3}{4}=\frac{2 \times 4+3 \times 5}{20}\)

= \(\frac{8+15}{20}=\frac{23}{20}=1 \frac{3}{20} \mathrm{~m}\)

Question 3.

Naina was given 1\(\frac{1}{2}\) piece of cake and Najma was given 1\(\frac{1}{3}\) piece of cake.

Find the total amount of cake given to both of them.

Solution:

Cake given to Naina = 1\(\frac{1}{2}\) = \(\frac{3}{2}\)

Cake giveen to Najma = 1\(\frac{1}{3}\) = \(\frac{4}{3}\)

∴ Total amount of cake given to both of them

= \(\frac{3}{2}+\frac{4}{3}=\frac{3 \times 3+2 \times 4}{6}\)

= \(\frac{9+8}{6}=\frac{17}{6}=2 \frac{5}{6}\)

Question 4.

Fill in the boxes:

Solution:

Question 5.

Complete the addition, subtraction box.

Solution:

Question 6.

A piece of wire 7/8 metre long broke into two pieces. One piece was 1/4 metre long. How long is the other piece ?

Solution:

Total length of a piece of wire = \(\frac{7}{8}\) m

Length of one piece = \(\frac{1}{4}\) m

∴ Length of the other piece = \(\frac{7}{8}-\frac{1}{4}=\frac{7-2}{8}=\frac{5}{8}\)m

Question 7.

Nandni’s house is \(\frac{9}{10}\) km. from her school. She walked some distance and then took a bus for \(\frac{1}{2}\) km upto the school. How far did she walk ?

Solution:

Total distance between house and school = \(\frac{9}{10}\) km

Distance covered by bus = \(\frac{1}{2}\) km

∴ Distance walked by her = \(\frac{9}{10}-\frac{1}{2}=\frac{9-5}{10}\)

= \(\frac{4}{10}=\frac{2}{5}\) km.

Question 8.

Asha and Samuel have bookshelves of the same size. Asha’s shelf is \(\frac{5}{6}\) full of books and Samuel’s shelf is \(\frac{2}{5}\) full. Whose bookshelf is more full ? By what fraction?

Answer:

Asha’s shelf is \(\frac{5}{6}\) full of books,

Samuel’s shelf is \(\frac{2}{5}\) full of books

Now, \(\frac{5}{6}-\frac{2}{5}=\frac{5 \times 5-2 \times 6}{30}=\frac{25-12}{30}=\frac{13}{30}\)

∴ Asha’s bookshelf is more full by \(\frac{13}{30}\) fraction.

Question 9.

Jaydev takes 2\(\frac{1}{5}\) minutes to walk across the school ground. Rahul takes \(\frac{7}{4}\) minutes to do the same. Who takes less time and by what fraction ?

Solution:

Time taken by Jaydev to walk across the school ground = \(2 \frac{1}{5}=\frac{11}{5}\) minutes

Time taken by Rahul to do the same = \(\frac{7}{4}\) minutes

Now, \(\frac{11}{5}-\frac{7}{4}=\frac{11 \times 4-5 \times 7}{20}=\frac{44-35}{20}=\frac{9}{20}\)

∴ Rahul takes less time by \(\frac{9}{20}\) fraction.