Class 6

Haryana State Board HBSE 6th Class Maths Solutions Chapter 9 Data Handling Ex 9.4 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 9 Data Handling Exercise 9.4

Question 1.
A survey of 120 school students was done to find which activity they prefer to do in their free time. Draw a bar graph to illustrate the given data taking scale of 1 unit length = 5 students.

Which activity is preferred by most of the students other than playing ?

Solution:
Reading books is preferred by most of the students other than playing.

Question 2.
Following table shows the number of bicycles manufactured in a factory during the years 1998 to 2002. Illustrate this data using a bar graph. Choose a scale of your choice.
Years — No. Manufactured of Bicycles
1998 — 800
1999 — 600
2000 — 900
2001 — 1100
2002 — 1200
(a) In which year were the maximum number of bicycles manufactured ?
(b) By looking at the bar graph, write which two years show the maximum rise in the manufacture of bicycles ?
Solution:
(a) In 2002, maximum number of bicycles were manufactured.

(b) 2000 and 2001 show the maximum rise in the manufacture of bicycles.

Question 3.
Number of persons in various age groups in a town is given in the following table :
Age group — No. of persons
1-14 — 2 lakh
15-29 — 1 lakh 60 thousand
30-44 — 1 lakh 20 thousand
45-59 — 1 lakh 20 thousand
60-74 — 80 thousand
75 and above — 40 thousand
Draw the bar graph to represent the above information and answer the following questions (take 1 unit length = 20 thousand)
(a) Which two age groups have the same population ?
(b) All persons in the age group of 60 and above are called senior citizens. How many senior citizens are there in the town ?
Solution:

(а) 30-44 and 45-59 have the same population.
(b) .80,000 + 40,000 = 1,20,000 are senior citizens.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 9 Data Handling Ex 9.3 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 9 Data Handling Exercise 9.3

Question 1.
Bar graph given below shows the amount of wheat purchased by government during the year 1998-2002.

Read the bar graph andi write down your observations.
Solution:
Year — Amount of wheat purchased
1998 — 15 thousand tons
1999 — 25 thousand tons
2000 — 20 thousand tons
2001 — 20 thousand tons
2002 — 30 thousand tons

Question 2.
Observe this bar graph which is showing the sale of shirts in a ready¬made shop from Monday to Saturday. Now answer the following questions :

(a) What information is given by the above bar graph ?
(b) Mention the scale chosen on the vertical line representing the no. of shirts.
(c) Mention the day on which the maximum number of shirts were sold and also mention the number of shirts sold.
(d) Mention the day on which the minimum number of shirts were sold.
(e) How many shirts were sold on Thursday ?
Solution:
(a) This bar graph shows the number of shirts sold from Monday to Saturday.
(b) 1 unit = 5 shirts.
(c) The maximum no. of shirts 60 were sold on Saturday.
(d) The minimum no. of shirts were sold on Tuesday.
(e) On Thursday, 35 shirts were sold.

Question 3.
Observe this bar graph which is showing the marks obtained by Aziz in half-yearly examination in different subjects. Answer the questions given below :

(a) What information is given by the bar graph ?
(b) Name the subject in which Aziz has scored maximum marks ?
(c) Name the subject in which he has scored minimum marks ?
(d) State the names of the subjects and marks obtained in each of them ?
Solution:
(a) This bar graph shows the marks obtained by Aziz in different subjects.
(b) Hindi (c) Social Studies
(d) Subjects — Marks obtained
(i) Hindi — 80
(ii) English — 60
(iii) Mathematics — 70
(iv) Science — 65
(v) Social Studies — 55

Question 4.
Following is a bar graph of circu¬lation of newspapers (dailies) in a town in six languages. Study the bar graph and answer the following questions :

(a) Find the number of newspapers circulated in Hindi, Punjabi, Urdu, Marathi and Tamil.
(b) Name the language in which the least no. of newspapers are circulated.
(c) What is the difference between the no. of Hindi and English papers being read ?
(d) Write the no. of newspapers circulated in different languages in ascending order.
Solution:
(a) Hindi—800, Punjabi—400, Urdu—200, Marathi—300, Tamil—100.
(b) Least no. of newspapers are circulated in Tamil.
(c) Difference between Hindi and English papers = 800 -500 = 300.
(d) 100, 200, 300, 400, 500, 800.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 9 Data Handling Ex 9.2 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 9 Data Handling Exercise 9.2

Question 1.
Total number of animals in five villages are as follows :
Village A : 80
Village B : 120
Village C : 90
Village D : 40
Village E : 60
Prepare a pictograph of these animals using one symbol 0 to represent 10 animals and answer the following questions :
(a) How many symbols represent animals of village E ?
(b) Which village has the maximum number of animals ?
(c) Which village has more animals : village A or village C ?
Solution:

(a) 6, (6) B, (c) C.

Question 2.
Total number of students of a school in different years is shown in the following table :
Year — Number of students
1996 — 400
1998 — 535
2000 — 472
2002 — 600
2004 — 623
A. Prepare a pictograph of students using one symbol represent 100 students and answer the following questions :
(a) How many symbols represent total number of students in the year 2002 ?
(b) How many symbols represent total number of students for the year 1998 ?
Solution:

(a) 6, (b) 5 complete and 1 incomplete.

B. Prepare another pictograph of students using any other symbol each representing 50 students. Which pictograph do you find more informative ?
Solution:

Second pictograph is more informative.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 9 Data Handling Ex 9.1 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 9 Data Handling Exercise 9.1

Question 1.
In a mathematics test, the following marks were obtained by 40 students. Arrange these marks in a table using tally marks.
(a) Find how many students obtained marks equal to or more than 7 ?
(b) How many students obtained marks below 4 ?

Solution:

(a) 12 students obtained marks equal to or more than 7.
(b) 8 students obtained marks below 4.

Question 2.
Following is the choice of sweets of 30 students of class VI.
Ladoo, Barfi, Ladoo, Jalebi, Ladoo, Rasgulla,
Jalebi, Ladoo, Barfi, Rasgulla, Ladoo, Jalebi,
Jalebi, Rasgulla, Ladoo, Rasgulla, Jalebi, Ladoo,
Rasgulla, Ladoo, Ladoo, Barfi, Rasgulla, Rasgulla,
Jalebi, Rasgulla, Ladoo, Rasgulla, Jalebi, Ladoo
(a) Arrange the names of sweets in a table using tally marks.
(b) Which sweet is preferred by most of the students ?
(c) Choose any symbol representing one student and make apictograph showing the choices.
Solution:

(b) Ladoo is preferred by most of the students.
(c) Pictograph.

Question 3.
Following pictograph shows the number of tractors in 5 villages :

Observe the pictograph and answer the following questions :
(i) Which village has the minimum number of tractors ?
(ii) Which village has the maximum number of tractors ?
(iii) How many more tractors village C has as compared to village B ?
(iv) What is the total number of tractors in all the five villages ?
Solution:
(i) Village D has minimum number of tractors.
(ii) Village C has maximum number of tractors.
(iii) Village C has 3 more tractors as compared to village B.
(iv) 6 + 5 + 8 + 3 + 6 = 28. The total number of tractors in all the five villages = 28.

Question 4.
The sale of electric bulbs on different days of a week is shown below :

Observe the pictograph and answer the following questions :
(a) How many bulbs were sold on Friday ?
(b) On which day were the maximum num ber of bulbs sold ?
(c) If one bulb were sold at the rate ofRs. 10, what was the total sale on Sunday ?
(d) Can you find out the total sale of the week ?
(e) If one big carton can hold 9 bulbs, how many cartons were needed in the given week, more than 4, more than 5 or more than 6 ?
Solution:
(a) 7 x 2 = 14 bulbs were sold on Friday.
(b) The maximum number of bulbs (18) were sold on Sunday.
(c) Total sale on Sunday = Rs. 10 x 18 = Rs. 180.
(d) Total sale of the week = Rs. 10 x 86 = Rs. 860.
(e) No. of cartons needed = 86 ÷ 9 = 9\(\frac{5}{9}\), i.e. more than 6.

Question 5.
The number of girl students in each class of a co-ed middle school is depicted by the following pictograph :

Observe this pictograph and answer the following questions :
(a) Which class has the minimum number of girl students ?
(b) Is the number of girls in class VI less than the number of girls in class V ?
(c) How many girls are there in class VII ?
(d) What other inferences can you draw from this pictograph ?
Solution:
(a) Class VIII has the minimum number of girl students (6).
(b) No, the number of girl students in class VI are not less than the number of girls in class V.
(c) In class VII, there are 12 girl students.
(d) This pictograph shows that the maximum number of girl students (24) are in class I and the total number of girls in the school are 120.

Question 6.
In a village, six fruit merchants sold the following number of fruit baskets in a particular season :

Observe this pictograph and answer the following questions :
(a) Which merchant sold the maximum number of baskets ?
(b) How many fruit baskets were sold by Anwar ?
(c) The merchants who have sold 600 or more number of baskets are planning to buy a godown for the next season. Can you name them ?
Solution:
(a) Martin sold the maximum number of baskets.
(b) 700 fruit baskets were sold by Anwar.
(c) Anwar, Martin and Ranjit Singh.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 8 Decimals Ex 8.3 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 8 Decimals Exercise 8.3

Question 1.
Which is greater ? Give reason for your answer ?
(a) 0.3 or 0.4
(b) 0.07 or 0.02
(c) 3 or 0.8
(d) 0.5 or 0.05
(e) 0.052 or 0.11
(f) 2.012 or 0.99
(g) 1 or 0.89
(h) 1.23 or 1.2
(i) 0.099 or 0.19
(j) 1.5 or 1.50
(k) 1.431 or 1.490
(l) 3.3 or 3.300
(m) 5.64 or 5.603
(n) 1.008 or 1.800
(o) 1.52 or 2.05.
Solution:

(p) Make 5 more examples and find the greater number from them.
(i) 0.040 or 0.404
(ii) 0.637 or 0.6
(iii) 0.27 or 0.72
(iv) 6.4 or 6.04
(v) 3.40 or 3.04.
Solution:
(i) 0.404 = 0 + \(\frac{4}{100}\) and 0.404 = 0 + \(\frac{4}{10}+\frac{4}{1000}\) ∴ 0.404 > 0.040.
0.637 = 0 + \(\frac{6}{10}+\frac{3}{100}+\frac{7}{1000}\) and 0.6 = 0 + \(\frac{6}{10}\) ∴ 0.637 > 0.6.
0.27 = 0 + \(\frac{2}{10}+\frac{7}{100}\) + and 0.72 0 + \(\frac{7}{10}+\frac{2}{100}\) ∴ 0.72 > 0.27
6.4 = 6 + \(\frac{4}{10}\) and 6.04 = 6 + \(\frac{4}{100}\) ∴ 6.4 > 6.04.
3.40 = 3 + \(\frac{4}{10}\) and 3.04 = 3 + \(\frac{4}{100}\) ∴ 3.40> 3.04.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 8 Decimals Ex 8.4 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 8 Decimals Exercise 8.4

Question 1.
Express a rupees using decimals:
(a) 5 paise
(b) 75 paise
(c) 3 rupees 60 paise
(d) 450 paise
(e) 20 paise
(f) 50 rupees 90 paise
(g) 725 paise.
Solution:
(a) 5 paise = Re \(\frac{5}{100}\) = Re 0.05
(b) 75 paise = Re \(\frac{75}{100}\) = Re 0.75
(c) 3 rupees 60 paise = 3 + \(\frac{60}{100}\) = 3 + 0.60 = Rs. 3.60
(d) 450 paise = Rs. \(\frac{450}{100}\) = Rs . 4.50
(e) 20 paise = Re\(\frac{20}{100}\) = Re 0.20.
(f) 50 rupees 90 paise = 50 + \(\frac{90}{100}\) = 50 + 0.90 = Rs. 50.90
(g) 725 paise. = Rs. \(\frac{725}{100}\) = Rs. 7.25

Question 2.
Express as m using decimals
(a) 15 cm
(b) 6 cm
(c) 136 cm
(d) 2 m 45 cm
(e) 9 m 7 cm
(f) 419 cm.
Solution:
(a) 15 cm = \(\frac{15}{100}\)m = 0.15 m.
(b) 6 cm = \(\frac{6}{100}\)m = 0.06 m.
(e) 136 cm =\(\frac{136}{100}\) m =1.36 m.
(d) 2m 45cm = 2 + \(\frac{45}{100}\) = 2 + 0.45
= 2.45 m.
(e) 9m7cm = 9 + \(\frac{7}{100}\)
9 + 0.07 = 9.07 m.
(f) 419 cm = \(\frac{419}{100}\) m = 4.19 m.

Question 3.
Express as cm using decimals :
(a) 5 mm
(b) 60 mm
(c) 164 mm
(d) 9 cm 8 mm
(e) 16 cm 7 mm.
(f) 93 mm.
Solution:
(a) 5 mm = \(\frac{5}{10}\) cm = 0.5 cm.
(b) 60 mm = \(\frac{60}{10}\) = 6 cm
(c) 164 mm = \(\frac{164}{10}\) = 16.4 cm
(d) 9 cm 8 mm = (9 + \(\frac{8}{10}\)) = 9.8 cm
(e) 16 cm 7 mm. = (16 + \(\frac{7}{10}\)) cm = (16 + 0.7) cm = 16.7 cm.
(f) 93 mm. = \(\frac{93}{10}\) cm = 9.3 cm

Question 4.
Express as km. using decimals
(a) 8 m
(b) 88 m
(c) 888 m
(d) 8888 m
(e) 70 km 5 m
(f) 29 km 37 m.
Solution:
(a) 8m = \(\frac{8}{1000}\) km = 0.008km.
(b) 88 m = \(\frac{88}{1000}\)km 0.088 km.
(c) 888 m = \(\frac{888}{1000}\)km = 0.888 km.
(d) 8888m = \(\frac{8888}{1000}\) km = 8.888km.
(e) 70 km 5 m = (70 + \(\frac{5}{1000}\)) km
= (70 + 0.005)
= 70.005 km.
(f) 29 km 37 rn = (29 + \(\frac{37}{1000}\)) km
= (29 + 0.037)
= 29.037 km.

Question 5.
Express as kg using decimals
(a) 2g
(b) 100 g
(c) 3750 g
(d) 2 kg 700 g
(e) 5 kg 8 g
(f) 26 kg 50 g.
Solution:
(a) 2 g = \(\frac{2}{1000}\) kg = 0.002 kg.
(b) 100 g kg = \(\frac{100}{1000}\) kg = 0.1 kg.
(c) 3750 g = \(\frac{3750}{1000}\) kg = 3.750 kg.
(d) 2kg700g = (2 + \(\frac{700}{1000}\)) kg
= (2 + 0.7) kg 2.7 kg.
(e) 5kg8g = (5 + \(\frac{8}{1000}\)) kg
= (5 + 0.008) kg
= 5.008 kg.
(f) 26 kg 50 g = (26 + \(\frac{50}{1000}\)) kg
= (26 + 0.05) kg = 26.05 kg.

Question 6.
Express each of the following without decimals :
(a) Rs. 2.30
(b) 9.240 kg
(c) 3.5 cm
(d) 3.05 km
(e) 8.81 m
(f) Rs. 13.05
(g) 15.038 km
(h) 14.007 kg
(i) 11.06 m
(j) 0.2 cm.
Solution:
(a) Rs. 2.30 = 2 Rs. 30 paise = 230 paisa.
(b) 9.240 kg = 9 kg 240 g = 9240 g.
(c) 3.5 cm = 3 cm 5 mm = 35 mm.
(d) 3.050 km = 3 km 50 m = 3050 m.
(e) 8.81 m = 8 m 81 cm = 881 cm.
(f) Rs. 13.05 = 13 Rs. 5 paise = 1305 paisa.
(g) 15.038 km = 15 km 38 m = 15038 m.
(h) 14.007 kg = 14 kg 7 g = 14007 g.
(i) 11.06 m = 11 m 6 cm = 1106 cm.
(j) 0.2 cm = 2 mm.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 8 Decimals Ex 8.5 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 8 Decimals Exercise 8.5

Question 1.
Find the sum in each of the following :
(a) 0.007 + 8.5 + 30.08
(b) 15 + 0.632 + 13.8
(c) 27.076 + 0.55 + 0.004
(d) 25.65 + 9.005 + 3.7
(e) 0.75 + 10.425 + 2
(f) 280.69 + 25.2 + 38.
Solution:

Question 2.
Rashid spent Rs. 35.75 for Maths book and Rs. 32.60 for Science book. Find the total amount spent by Rashid.
Solution:

Question 3.
Radhika’s mother gave her Rs. 10.50 and her father gave her Rs. 15.80, find the total amount given to Radhika by her parents.
Solution:

Question 4.
Narseen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trousers. Find the total length of cloth bought by her.
Solution:
Length of cloth bought by Narseen for her shirt = 3 m 20 cm = 3.20 m
Length of cloth bought by her for trousers = 2 m 5 cm = 2.05 m ,
∴  Total length of cloth bought by her 3.20 m + 2.05 m
= 5.25 m = 5 m 25 cm.

Question 5.
Wilson bought 2 m 50 cm cloth for his kurta and 1 m 25 cm cloth for his pyjama. Find the total length of cloth bought by him.
Solution:
Length of cloth bought by Wilson for his kurta = 2 m 50 cm = 2.50 m
Length of cloth bought by him for his pyjama = 1 m 25 cm = 1.25 m
∴ Total length of cloth bought by him = 2.50 m + 1.25 m

Haryana State Board HBSE 6th Class Maths Solutions Chapter 8 Decimals Ex 8.6 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 8 Decimals Exercise 8.6

Question 1.
Subtract :
(a) Rs. 18.25 from Rs. 20.75
(b) 202.54 m from 250 m
(c) Rs. 5.36 from Rs. 8.4
(d) 2.051 km from 5.206 km
(e) 0.314 kg from 2.107 kg.
Solution:

Question 2.
Find the value of 2
(a) 9.756- 6.28
(b) 21. 05 – 15.27
(c) 18.5-6.79
(d) It. 6-9.847
Solution:

Question 3.
Raju bought a book for Rs. 35.65. He gave Rs. 50 to the shopkeeper. How much money did he get back from the shopkeeper ?
Solution:
Amount given by Raju to the Shopkeeper = Rs. 50.00
Price of the book lie bought = Rs. 35.65
∴ Amount he get back from the Shopkeeper = Rs. 50.00 – Rs. 35.65
= Rs. 14.35.

Question 4.
Rani had Rs. 18.50. She bought one ice-cream for Rs. 11.75. How much money does she have now ? j
Solution:
Money which Rani had with her = Rs. 18.50
Price of one ice-cream which’ she bought = Rs. 11.75 .
∴ Money which she has now = Rs. 18.50 – Rs. 11.75
= Rs. 6.75

Question 5.
Tina had 20 m 5 cm long cloih. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her ?
Solution:
Length of the cloth Tina has = 20 m 5 cm = 20.05 m
Length of cloth cut for making a curtain = 4 m 50 cm = 4.50 m
∴ Length of cloth left with her = 20.05 m – 4.50 m
= 15.55 m

Question 6.
Namita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto ?
Solution:
Total distance travelled by Namita = 20 km 50 m = 20.050 km
Distance travelled by her by bus = 10 km 200 m = 10.200 km
∴ Distance travelled by her by auto = (20.050 – 10.200) km
= 9.850 km.

Question 7.
Aakash bought vegetables weighing 10 kg. Out of this 3 kg 500 g is onion, 2 kg 75 g is tomato and the rest is potato. What is the weight of potato ?
Solution:
Total weight/of vegetables = 10 kg
Weight of onion = 3 kg 500 g = 3.500 kg
∴ Weight of tomato = 2 kg 75 g
= 2.075 kg

Question 8.
Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all ? \
Solution:
Distance walked by Naresh in the morning = 2 km 35 m = 2.035 km
Distance walked by him in thte evening = 1 km 7 m = 1.007 km
∴ Total distance walked by him = (2.035 + 1.007) km
= 3.042 km.

Question 9.
Sunita travels 15 km 268 m by busl 7 km 7 m by car and 500 m by foot in order to reach her school. How far is her school from her residence ?
Solution:
Distance travelled by Sunita by bus = 15 km 268 m = 15.268 km
Distance travelled by her by car = 7 km 7 m = 7.007 km
Distance travelled by her by foot = 500 m = 0.500 km
∴ Total distance = (15.268 + 7.007 + 0.500) km
= 22.775 km.

Question 10.
Ravi purchased 5 kg 400 g rice, 2 the total weight of his purchases.
Solution:
Weight of rice = 5 kg 400 g = 5.400 kg
Weight of sugar = 2 kg 20 g = 2.020 kg
Weight of atta = 10 kg 890 g = 10.850 kg
∴ Total weight = (5.400 + S2.020 + 10.850) kg
= 18.270 kg.

Haryana State Board HBSE 6th Class Maths Solutions Chapter 8 Decimals Ex 8.2 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 8 Decimals Exercise 8.2

Question 1.
Complete the table with the help of these boxes and use decimals to write the number :

Solution:

Question 2.
Write the numbers given in the following place value table in decimal form:

Solution:
(i) The number is 3 x 1 + 2 x \(\frac{1}{10}\) + 5 x \(\frac{1}{100}\) = 3 + 0.2 + 0.05 = 3.25.
(ii) Thenumberis 1 x 100 + 0 x 10 + 2 x 1 + 6 x \(\frac{1}{10}\) + 3 x \(\frac{1}{100}\)
= 100 + O + 2 + 0.6 + 0.03 = 102.63.
(iii) The number is 3 x 10 + 0 x 1 + 0 x \(\frac{1}{10}\) + 2 x \(\frac{1}{100}\) + 5 x \(\frac{1}{1000}\)
= 30 + 0 + 0 + 0.02 + 0.005 = 30.025.
(iv) The numberis 2 x 100+ 1 x 10 + 1 x 1 + 9 x \(\frac{1}{10}\) + 0 x \(\frac{1}{100}\) + 2 x \(\frac{1}{1000}\)
= 200 + 10 + 1 + 0.9 + 0.00 + .002 = 211.902.
(v) The number is 1 x 10 + 2 x 1 + 2 x \(\frac{1}{10}\) + 4 x \(\frac{1}{100}\) + 1 x \(\frac{1}{1000}\)
= 10 + 2 + 0.2 + 0.04 + 0.001 = 12.241.

Question 3.
Write the following decimals in the place value table :
(a) 0.29, (b) 2.08, (c) 19.60, (d) 148.32, (e) 200.812.
Solution:

Question 4.
Write each of the following as decimals :

Solution:

Question 5.
Write each of the following decimals in words :
(a) 0.03
(b) 1.20
(c) 17.38
(d) 108.56
(e) 10.07
(f) 210.109
(g) 0.032
(h) 5.008.
Solution:
(a) 0.03 = Zero point zero three or three hundredths.
(b) 1.20 = One point two zero.
(c) 17.38 = Seventeen point three eight.
(d) 108.56 = One hundred eight point five six.
(e) 10.07 = Ten point zero seven.
(f) 210.109 = Two hundred ten point one zero nine.
(g) 0.032 = Zero point zero three two.
(h) 5.008 = Five point zero zero eight.

Question 6.
Between which two points numbers on the number line does each of the given number lie ?
(a) 0.06
(b) 0.45
(c) 0.19
(d) 0.66
(e) 0.92
(f) 0.57
(g) 0.03
(h) 0.20.
Solution:
All the given numbers lie between whole number 0 and 1.
(a) 0 and 0.1, nearer to the number 0.1.
(b) 0.4 and 0.5, nearer to the number 0.5.
(c) 0.1 and 0.2, nearer to the number 0.2.
(d) 0.6 and 0.7, nearer to the number 0.7.
(e) 0.9 and 1.0, nearer to the number 0.9.
(f) 0.5 and 0.6, nearer to the number 0.6.
(g) 0.0 and 0.1, nearer to the number 0.0.
(h) 0.1 and 0.3, nearer to the number 0.2.

Question 7.
Write as fractions in the lowest terms :

(a) 0.60
(b) 0.05
(c) 0.75
(d) 0.18
(f) 0.82
(g) 0.004
(h) 0.125.
(i) 0.066.
Solution:

Haryana State Board HBSE 6th Class Maths Solutions Chapter 8 Decimals Ex 8.1 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 8 Decimals Exercise 8.1

Question 1.

Solution:

Question 2.
Write the following decimals in the (a) 19.4 (6) 0.3 (c) 10.6 (d) 205.9
Solution:

Question 3.
Write each of the following as decimals:
(a) 7 tenths
(b) Two tens, 9 tenths
(c) Fourteen point six
(d) One Hundred and 2 ones
(e) Six hundred point eight.
Solution:
(a) 7 tenths = \(\frac{7}{10}\) = 0.7
(b) Two tens, 9 tenths = 20 + \(\frac{9}{10}\) = 20.9.
(c) Fourteen point six = 14.6.
(d) Hundred and two ones = 102.0.
(e) Six hundred point eight = 600.8.

Question 4.
Write each of the following as decimals:

Solution:

Question 5.
Write the following decimals as fractions. Reduce the fractions to their lowest forms : (a) 0.6, (b) 2.5, (c) 1.0, (d) 3.8, (e) 13.7, (f) 21.2, (g) 6.4.
Solution:
(a) 0.6 = \(\frac{6}{10}=\frac{3}{5}\)
(b) 2.5 = \(\frac{25}{10}=\frac{5}{2}\)
(c) 1.0 = 1.
(d) 3.8 = \(\frac{38}{10}=\frac{19}{5}\)
(e) 13.7 = \(\frac{137}{10}\)
(f) 21.2 = \(\frac{212}{10}=\frac{106}{5}\)
(g) 6.4 = \(\frac{64}{10}=\frac{32}{5}\)

Question 6.
Express the following as cm using decimals :
(a) 2 mm
(b) 30 mm
(c) 116 mm
(d) 4 cm 2 mm
(e) 162 mm
(f) 83 mm.
Solution:
(a) 2 mm = \(\frac{2}{10}\) = 0.2 cm.
(b) 30 mm = \(\frac{30}{10}\) = 3.0 cm
(c) 116 mm = \(\frac{116}{10}\) = 11.6 cm
(d) 4 cm 2 mm = 4 +\(\frac{2}{10}\) = 4.2 cm
(e) 162mm = 11 + \(\frac{52}{10}\) = 11 + 5.2 = 16.2 cm.
(f) 83 mm =\(\frac{83}{10}\) = 8.3 cm.

Question 7.
Between which two whole numbers on the number line are the given numbers ? Which one is nearer the number ?
(a) 0.8, (b) 5.1, (c) 2.6, (d) 6.4, (e) 9.0, (f) 4.9.

Solution:
(a) 0-1, and nearer to the number 1.
(b) 5-6, and nearer to the number 5.
(c) 2-3, and nearer to the number 3.
(d) 6-7, and nearer to the number 6.
(e) 8-10, and nearer to the number 9.
(f) 4-5, and nearer to the number 5.

Question 8.
Show the following decimal numbers on the number line :
(a) 0.2,
(b) 1.9,
(c) 1.1,
(d) 2.5.
Solution:

Question 9.
Write the decimal number represented by the points A, B, C and D on the given number line :

Solution:
(i) Point A represents the number 0.8.
(ii) Point B represents the number 1.3
(iii) Point C represents the number 2.2
(iv) Point D represents the number 2.9.

Question 10.
(a) The length of Ramesh’s notebook is 9 cm 5 mm. What will be its length in cm ?
(b) The length of a young gram plant is 65 mm. Express its length in cm.
Solution:
(a) 9 cm 5 mm = 9 + \(\frac{5}{10}\) = 9.5 cm (b) 65 mm = \(\frac{65}{10}\) = 6.5 cm.