HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2

Haryana State Board HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2 Textbook Exercise Questions and Answers.

Haryana Board 8th Class Maths Solutions Chapter 4 Practical Geometry Exercise 4.2

Question 1.
Construct the following quadrilaterals :
(i) Quadrilateral
LIFT
LI = 4 cm
IF = 3 cm
TL = 2.5 cm
LF = 4.5 cm
IT = 4 cm
(ii) Quadrilateral
GOLD
OL = 7.5 cm
GL = 6 cm
GD = 6 cm
LD = 5 cm
OD = 10 cm
(iii) Rhombus BEND
BN = 5.6 cm, DE = 6.5 cm
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2 1
Solution:
(i) Rough sketch:
You will observe that the measurements of all the sides of △LFI are given. So, draw △LFI first.
Steps of Construction :
(i) Take a line segment LF = 4.5 cm.
(ii) With centre as L and F cut off arcs of radii 4 cm and 3 cm respectively.
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2 2
(iii) You will get △LFI.
(iv) Now, with L and I as centre cut off arcs of length TL = 2.5 cm and TI = 4 cm.
(v) Join TI, TL and TF.
(vi) You will get the required quadrilateral.

HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2

(ii) Rough Sketch:
Here, GL = 6 cm, GD = 6 cm and LD = 5 cm.
So, you can draw a △GLD quite easily.
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2 3
Steps of Construction :
(i) Take a line segment GL = 6 cm.
(ii) Cut off GD = 6 cm and LD = 5 cm.
(ui) Join GD and LD.
(iv) You will obtain a △GLD.
(v) Now, with L and D as centre cut off two arcs of length 7.5 cm and 10 cm respectively to obtain a point O.
(vi) Join OL, OD and OG.
(vii) You will get a quadrilateral GOLD.
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2 4

HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2

(iii) Rough Sketch:
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2 5
OB = ON = \(\frac{5.6}{2}\) = 2.8 cm
∠BOD = ∠BOE = ∠EON = ∠BOD = 90°
[Diagonals of a Rhombus bisect each other at 90°]
Steps of Construction :
(i) Draw DE = 6.5 cm.
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2 6
(ii) Draw perpendicular bisector XY of DE
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2 7
(iii) Cut off an arc of OB = 2.8 cm with O as centre and ON = 2.8 cm on the line XY as indicated.
(iv) Join BD, BE, EN and DN.
(v) You will get the required rhombus BEND
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.2 8

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