Haryana State Board HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.3 Textbook Exercise Questions and Answers.

## Haryana Board 8th Class Maths Solutions Chapter 4 Practical Geometry Exercise 4.3

Question 1.

Construct the following quadrilaterals :

(i) Quadrilateral

MORE

MO = 6 cm

OR = 4.5 cm

∠M = 60°

∠O = 105°

∠R = 105°

(ii) Quadrilateral

PLAN

PL = 4 cm

LA = 6.5 cm

∠P = 90°

∠A= 110°

∠N = 85°

(iii) Parallel

HEAR

HE = 5 cm

EA = 6 cm

∠R = 85°

(iv) Quadrilateral

PLAN

OK = 7 cm

KA = 5 cm

Solution:

(i) Rough Sketch:

Steps of Construction :

(i) Take a line segment MO = 6 cm.

(ii) Construct ∠MOR = 105° and cut off OR = 4.5 cm.

(iii) At R construct ∠ORX = 105°.

(iv) Now, construct ∠OMY = 60°.

(v) Let MY intersect RX at E.

(vi) Thus, MORE is the required quadrilateral.

(ii) Rough Sketch:

Steps of Construction :

(i) Draw a line segment PL = 4 cm.

(ii) Construct ∠P = 90°, ∠L = 85° and cut off ∠A = 6.5 cm in ∠X.

(iii) Construct ∠YPL = 90°

(iv) PY intersect AZ at N.

(v) PLAN is required quadrilateral.

(iii) Rough Sketch:

Steps of Construction :

(i) Take HE = 5 cm.

(ii) Draw ∠HEA = 85° and cut off EA = 6 cm in EX.

(iii) ∠H = 108° – 85° = 95°

(iv) Construct ∠EHY = 95° and cut off HR = 6 cm.

(v) Join HR and RA.

(vi) We have a parallelogram HEAR.

(iv) Rough Sketch:

We know that each angle of rectangle is 90° and opposite sides are equal.

Steps of Construction :

(i) Draw a line segment OK = 7 cm.

(ii) Construct ∠OKX = 90° and cut off KA = 5 cm.

(iii) Also, construct ∠KOZ = 90° and cut off OY = 5 cm.

(iv) Join OY and AY.

(v) OKAY is the required rectangle.