HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1

Haryana State Board HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 Textbook Exercise Questions and Answers.

Haryana Board 8th Class Maths Solutions Chapter 4 Practical Geometry Exercise 4.1

Question 1.
Construct the following quadrilaterals :
(i) Quadrilateral
ABCD
AB = 4.5 cm
BC = 5.5 cm
CD = 4 cm
AD = 6 cm
AC = 7 cm
(ii) Quadrilateral
JUMP
JU = 3.5 cm
UM = 4 cm
MP = 5 cm
PJ = 4.5 cm
PU = 6.5 cm
(iii) Parallelogram
MORE
OR = 6 cm
RE = 4.5 cm
EO = 7.5 cm
(iv) Rhombus
BEST
BE = 4.5 cm
ET = 6 cm
Solution:
(i) Rough sketch
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 1
Steps of Construction :
(a) Take a line segment AC = 7 cm.
(b) Draw an arc of radius AB = 4.5 cm taking A as centre.
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 2
(c) Draw another arc of radius 5.5 cm taking C as centre.
(d) Let these two arc intersect at B.
(e) You have a triangle, ABC.
(f) Repeat your construction to obtain △ADC taking AD = 6 cm and DC = 4 cm.
(g) You will obtain a quadrilateral ABCD
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 3

(ii) Rough sketch
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 4
Steps of Construction :
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 5
(a) Draw a line segment PU = 4 cm.
(b) Taking P as centre cut off an arc of radius 4.5 cm.
(c) Taking U as centre cut off another arc of radius 3.5 cm.
(d) Let these two arcs intersect at J.
(e) Join PJ and UJ.
(f) Similarly, obtain the point M on the opposite side of diagonal PU.
(g) Hence, you have a required quadrilateral JUMP Fig. 4.10.

HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1

(iii) Rough Sketch:
Here, OR = ME = 6 cm
and ER = MO = 4.5 cm.
[Opposite sides of a llgm are equal]
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 6
Steps of Construction :
(i) Cut off EM = 6 cm.
(ii) Now, cut off an arc of radius 4.5 cm.
(iii) Let the point of intersection of these two arcs be CM.
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 7
(iv) Join EM and MO.
(v) You have a AEMO.
(vi) Similarly, obtain △EOR with arc lengths ER = 4.5 cm and OR = 6 cm.
(vii) You will obtain a parallelogram MORE.

(iv) Rough Sketch :
Here, BE = BT = ST = ES = 4.5 cm
[All sides of rhombus are equal]
Steps of Construction :
(a) Draw ET = 6 cm.
(b) Cut off two arcs EB = BT = 4.5 cm. taking E and T as centre.
(c) Similarly, on the opposite side of ET take two arcs of equal length.
(d) You will obtain a rhombus BEST [Fig. 4.13]
HBSE 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 8

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