Haryana State Board HBSE 7th Class Maths Solutions Chapter 9 Rational Numbers InText Questions and Answers.

## Haryana Board 7th Class Maths Solutions Chapter 9 Rational Numbers InText Questions

Question 1.

Is the number \(\frac{2}{-3}\) rational number ?

Solution:

\(\frac{2}{-3}\) is a rational number.

Question 2.

List ten rational numbers.

Solution:

\(\frac{5}{2}, \frac{-3}{2}, 5,4,-1,-2, \frac{0}{1}, \frac{0}{-1}, \frac{0}{2}, \frac{-2}{3}\) are rational numbers.

Question 3.

Mention five rational numbers each of whose:

(a) Numerator is a negative integer and denominator is a positive integer.

(b) Numerator is positive integer and denominator is a negative integer.

(c) Numerator and denominator are both negative integers.

(d) Numerator and denominator are both positive integers.

Solution:

Question 4.

Fill in the boxes:

Solution:

Question 5.

Is 5 a positive rational number ?

Solution:

Yes, 5 is a positive rational number.

Question 6.

List five more positive rational number.

Solution:

\(\frac{5}{6}, \frac{-7}{-11}, \frac{5}{7}, \frac{36}{63}, \frac{17}{19}\)

Question 7.

Q. 1. Is – 8 a negative rational number ?

Solution:

Yes, – 8 is a negative rational number.

Question 8.

List five more negative rational number.

Solution:

\(\frac{-16}{6}, \frac{-8}{3}, \frac{-24}{9}, \frac{-32}{12}, \frac{-40}{15}\)

Question 9.

Which of these are negative rational numbers ?

(i) \(\frac{-2}{3}\)

(ii) \(\frac{5}{7}\)

(iii) \(\frac{3}{-5}\)

(iv) 0

(v) \(\frac{6}{11}\)

(vi) \(\frac{-2}{-9}\)

Solution:

Question 10.

Find the standard form of:

(i) \(\frac{-18}{45}\)

(ii) \(\frac{-12}{18}\)

Solution:

Question 11.

Find five rational number between \(\frac{-5}{7}\) and \(\frac{-3}{8}\)

Solution:

Now we have common denominator. Number between – 40 and – 21 are – 39, -38, – 37, – 36, – 35, – 20.

So, we can choose any five out of them.

Question 12.

Find:

(i) \(\frac{-13}{7}+\frac{6}{7}\)

(ii) \(\frac{19}{5}+\frac{-7}{5}\)

Solution:

Question 13.

Find:

(i) \(\frac{3}{7}+\frac{2}{3}\)

(ii) \(\frac{-5}{6}+\frac{-3}{11}\)

Solution:

Question 14.

What is additive inverse?

(i) \(\frac{-3}{9}\)

(ii) \(\frac{-9}{11}\) and

(iii) \(\frac{5}{7}\)

Solution:

(i) \(\frac{-3}{9}=\frac{3}{9}\)

(ii) \(\frac{-9}{11}=\frac{9}{11}\)

(iii) \(\frac{5}{7}=\frac{-5}{7}\)

Question 15.

Find:

(i) \(\frac{7}{5}-\frac{2}{5}\)

(ii) \(2 \frac{1}{5}-\frac{-1}{3}\)

Solution:

Question 16.

What are the multiplication?

(i) \(\frac{-3}{4} \times 7\)

(ii) \(\frac{-6}{5} \times(-2)\)

Solution:

Question 17.

Find:

(i) \(\frac{-3}{4} \times \frac{1}{7}\)

(ii) \(\frac{2}{3} \times \frac{-5}{9}\)

Solution:

(i) \(\frac{-3}{4} \times \frac{1}{7}=\frac{-3}{28}\)

(ii) \(\frac{2}{3} \times \frac{-5}{9}=\frac{-10}{27}\)

Question 18.

What will be the reciprocal of \(\frac{-6}{11}\)?\(\frac{-8}{5}\)?

Solution:

Question 19.

Find

\(\frac{2}{3} \times \frac{-7}{8}\)

Solution:

\(\frac{2}{3} \times \frac{-7}{8}=\frac{-14}{24}=\frac{-7}{12}\)

Question 20.

Find

\(\frac{-6}{7} \div \frac{5}{7}\)

Solution:

\(\frac{-6}{5} \div \frac{5}{7}=\frac{-6}{5} \times \frac{7}{5}=\frac{-42}{25}\)