HBSE 7th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.5

Haryana State Board HBSE 7th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.5 Textbook Exercise Questions and Answers.

Haryana Board 7th Class Maths Solutions Chapter 10 Practical Geometry  Exercise 10.5

Question 1.
Construct the right-angled ΔABC where m∠B = 90°, BC = 8 cm and AC = 10 cm.
Solution:
Steps of construction :
1. Draw a line segment QR = 8 cm.
2. At Q, construct ∠RQX = 90°.
3. With centre at R and radius 10 cm, draw an arc to cut \(\) at P.
4. Join PR.
Thus, ∠PQR is the required right angled triangle.
HBSE 7th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.5 1

HBSE 7th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.5

Question 2.
Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm. Long.
Solution:
Steps of Construction :
1. Draw a line segment MN = 4 cm.
2. Construct ∠NMX = 90° at M.
3. With centre at N and radius 6 cm, draw an arc to cut \(\overline{\mathrm{MX}}\) at L.
4. Join LN.
Thus, ΔLMN is the required right-angled triangle.
HBSE 7th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.5 2

HBSE 7th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.5

Question 3.
Construct an isoscales right¬angled triangle ABC where m∠ACB = 90° and AC = 4 cm.
Solution:
Steps of Construction :
1. Draw a line segment AC = 6 cm.
2. At C, construct, ∠ACX = 90°.
3. With centre C and radius = AC = 6 cm,
draw an arc to cut \(\overline{\mathrm{CX}}\) B.
4. Join BA.
Thus, ΔABC is the required isosceles right, angled triangle.

HBSE 7th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.5 3

Leave a Comment

Your email address will not be published. Required fields are marked *