HBSE 6th Class Maths Solutions Chapter 3 Playing With Numbers Ex 3.1

Haryana State Board HBSE 6th Class Maths Solutions Chapter 3 Playing With Numbers Ex 3.1 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 3 Playing With Numbers Exercise 3.1

Question 1.
Write all the factors of the following numbers :
(a) 24 (b) 15 (c) 21
(d) 27 (e) 12 (f) 20
(g) 18 (h) 23 (i) 36
Solution:
(a) 24 = 1 x 24
= 2 x 12
= 3 x 8
= 4 x 6
∴ All the factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24.

HBSE 6th Class Maths Solutions Chapter 3 Playing With Numbers Ex 3.1

(b) 15 = 1 x 15
= 3 x 5
∴ All the factors of 15 are 1, 3, 5, 15. Ans.

(c) 21 = 1 x 21
= 3 x 7
∴ All the factors of 21 are 1, 3, 7, 21. Ans.

(d) 27 = 1 x 27
= 3 x 9
∴ All the factors of 27 are 1, 3, 9, 27. Ans.

(e) 12 = 1 x 12
= 2 x 6
= 3 x 4
∴ All the factors of 12 are 1, 2, 3, 4, 6, 12.

(f) 20 = 1 x 20
= 2 x 10 = 4 x 5
∴ All the factors of 20 are 1, 2, 4, 5, 10, 20.

(g) 18 = 1 x 18
= 2 x 9 = 3 x 6
∴ All the factors of 18 are 1, 2, 3, 6, 9, 18.

(h) 23 = 1 x 23
∴ All the factors of 23 are 1, 23.

(i) 36 = 1 x 36
= 2 x 18 = 3 x 12 = 4 x 9 = 6 x 6
∴ All the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36.

Question 2.
Write the first five multiples of:
(a) 5 (b) 8 (c) 9
Solution:
(a) The required multiples of 5 are :
5 x 1 = 5
5 x 2 = 10
5 x 3 = 15
5 x 4 = 20
5 x 5 = 25.
i.e., 5, 10, 15, 20 and 25

HBSE 6th Class Maths Solutions Chapter 3 Playing With Numbers Ex 3.1

(b) The required multiples of 8 are :
8 x 1 = 8
8 x 2 = 16
8 x 3 = 24
8 x 4 = 32
8 x 5 = 40.
i.e., 8, 16, 24, 32 and 40

(c) The required multiples of 9 are :
9 x 1 = 9
9 x 2 = 18
9 x 3 = 27
9 x 4 = 36
9 x 5 = 45.
i.e., 9, 18, 27, 36 and 45.

Question 3.
Match the items in column 1 with the items in column 2 :
Column 1 — Column 2
(i) 35 — (a) Multiple of 8
(ii) 15 — (b) Multiple of 7
(iii) 16 — (c) Multiple of 70
(iv) 20 — (d) Factor of 30
(v) 25 — (e) Factor of 50
(f) Factor of 20
Solution:
(i) – (b) Multiple of 7
(ii) – (d) Factor of 30
(iii) – (a) Multiple of 8
(iv) – (f) Factor of 20
(v) – (e) Factor of 50

HBSE 6th Class Maths Solutions Chapter 3 Playing With Numbers Ex 3.1

Question 4.
Find all the multiples of 9 upto 100.
Solution:
9 x 1 = 9
9 x 2 = 18
9 x 3 = 27
9 x 4 = 36
9 x 5 = 45
9 x 6 = 54
9 x 7 = 63
9 x 8 = 72
9 x 9 = 81
9 x 10 = 90
9 x 11 = 99.
Hence all the multiples of 9 upto 100 are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99.

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