HBSE 6th Class Maths Solutions Chapter 14 Practical Geometry Intext Questions

Haryana State Board HBSE 6th Class Maths Solutions Chapter 14 Practical Geometry Ex 14.5 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 14 Practical Geometry Exercise

14.5

TRY THESE :

Question 1.
In step 2 above, what would happen if we take the length of radius to
be smaller than half the length of \(\overline{\mathrm{AB}}\) ?
Solution:
If we take the radius to be smaller than half of the length of \(\overline{\mathrm{AB}}\), the arcs will not intersect each other at two points C and D.

HBSE 6th Class Maths Solutions Chapter 14 Practical Geometry Intext Questions

TRY THIS (Page 380) :

Question 1.
How will you construct a 15° angle ?
Solution:
Construct of angle an 30° as shown earlier.
Now bisect this angle. We get ∠AOD = 15° [Fig.],
HBSE 6th Class Maths Solutions Chapter 14 Practical Geometry Intext Questions 1

TRY THESE (Page 381) :

Question 1.
How will you. construct a 150° angle ?
Solution:
Construct an angle of 120° as shown earlier.
Now ∠POQ = Straight angle – 180°
∠QOC = 120°
∠POC = 180° – 120° = 60°
HBSE 6th Class Maths Solutions Chapter 14 Practical Geometry Intext Questions 2
Bisect ∠POC to get ∠COD = 30°
Thus, ∠QOD = ∠QOC + ∠COD = 120° + 30° = 150° which is the required angle.

HBSE 6th Class Maths Solutions Chapter 14 Practical Geometry Intext Questions

TRY THESE
Question.
How will you construct a 45° angle ?
Solution:
Construct ∠QOC = 90° as shown earlier. Raw \(\overrightarrow{\mathrm{OD}}\) as the bisector of ∠QOC.
Thus, ∠QOD = 45° is the required angle.
HBSE 6th Class Maths Solutions Chapter 14 Practical Geometry Intext Questions 3

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