HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions

Haryana State Board HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions

Question 1.
Measure and write the length of the four sides of the top of your study table. What is the perimeter ?
Solution:
HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions 1
AB = 150 cm
BC = 75 cm
CD = 150 cm
DA = 75 cm
Now, the sum of the L lengths of the four sides
= AB + BC + CD + DA
= 150 cm + 75 cm + 150 cm + 75 cm
= 450 cm
Hence, perimeter = 450 cm.

HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions

Question 2.
Measure and write the length of the four sides of a page of your note- book. What is the perimeter of the page?
Solution:
The sum of the lengths of the four sides
= AB + BC + CD + DA
= 20 cm + 15 cm + 20 cm + 15 cm
= 70 cm
Hence, perimeter of the page = 70 cm.

Question 3.
Meera went to a park 150 m long and 80 m wide. She took one complete round of it. What is the distance covered by her ?
Solution:
AB = 150 m,
BC = 80 m
CD = 150 m,
DA = 80 m
∴ Distance covered by Meera
= AB + BC + CD + DA
= 150 m + 80 m + 150 m + 80 m
= 460 m.

Question 4.
Find the perimeter of the following rectangles
Solution:
HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions 2

HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions

Question 5.
Biswamitra wants to put coloured tape all around a square picture (Fig. 10.2) of side 1 m as shown. What will be the length of the coloured tape he requires ?
Solution:
Length of one side = 1m
Perimeter of the square = 4 x 1 m = 4 m
Hence, 4 m coloured tape will be required.
HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions 3

Question 6.
Now, look at equilateral triangle (10.3) with each side of 4 cm. Can you find its perimeter ?
HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions 4
Solution:
Length of one side = 4 cm
Perimeter of equilateral triangle = 3 x 4 cm
= 12 cm.

Question 7.
Draw any circle on a graph sheet. Count the squares and use them to estimate the area of the circular region.
Solution:
(i) Ignore the portions of the area that are less than half a square.
(ii) If more than half of a square is in a region, just count it as one square.
(iii) If exactly half the square is counted, take it simply as \(\frac{1}{2}\) sq. cm.
HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions 5

Cover Number Area estimated (sq. cm)
(i) Fully filled squares (√) 5 5
(ii) Half-filled squares (•) 2 2 x \(\frac{1}{2}\) = 1
(Hi) More than half-filled squares (Δ) 3 3
(iv) Less than half-filled squares (x) 6 0

Total area = 5 + 1 + 3 = 9sq. cm.

HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions

Question 8.
Trace the shape of a leave on the graph paper and estimate its area.
Solution:

Cover Number Area (in sq. cm)
(i) Fully filled squares (/) 1 1
(ii) Half-filled squares (•) 0 0
(iii) More than half-filled squares (A) 1 1
(iu) Less than half- filled squares (x) 5 0

Total area = 1 + 1 = 2 sq. cm.
HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions 6

Question 9.
Find the area of the floor of your classroom.
Solution:
Let length of the classroom = 7 m
and breadth of the classroom = 5 m
∴ Area of the classroom
= 7 m x 5 m = 35 sq. m.

Question 10.
Find the area of any one door in your house.
Solution:
Let length of the door = 3 m
and breadth of the door = 1.5 m
∴ Area of the door = 3 m x 1.5 m
= 4.5 sq. m.

Question 11.
Take a piece of 5 cm square paper and find its area.
Solution:
Side of the square = 5 cm
∴ Area of the square = side x side
= 5 cm x 5 cm = 25 cm2.

HBSE 6th Class Maths Solutions Chapter 10 Mensuration Intext Questions

Question 12.
The Jength of one side of a few squares is giyen, find their areas.
Solution:
Length of one side — Area of the square
3 cm = 3 x 3 = 9 sq. cm
7 cm = 7 x 7 = 49 sq. cm
4 cm = 4 x 4 = 16 sq. cm

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