Haryana State Board HBSE 8th Class Maths Solutions Chapter 1 Rational Numbers Ex 1.2 Textbook Exercise Questions and Answers.

## Haryana Board 8th Class Maths Solutions Chapter 1 Rational Numbers Exercise 1.2

Question 1.

Represent these numbers on the number line, (i) \(\frac{7}{4}\) (ii) \(\frac{-5}{6}\)

Solution:

(i) To represent \(\frac{7}{4}\), we make 7 marking of distance \(\frac{1}{4}\) each on the right of zero and starting from 0. The seventh marking is \(\frac{7}{4}\).

(ii) \(\frac{-5}{6}\)

To represent \(\frac{-5}{6}\), the number line may be divided into six equal parts. We make 6 marking of distance \(\frac{1}{6}\) each on the left of zero and starting from 0. The fifth marking is \(\frac{-5}{6}\).

Question 2.

Represent \(\frac{-2}{11}\), \(\frac{-5}{11}\), \(\frac{-9}{11}\) on the number line.

Solution:

To represent \(\frac{-2}{11}\), \(\frac{-5}{11}\), \(\frac{-9}{11}\). The number line may be divided into eleven equal parts. We make 11 marking of distance \(\frac{1}{11}\) each on the left of zero and starting from 0. The second fifth and ninth making are \(\frac{-2}{11}\), \(\frac{-5}{11}\), \(\frac{-9}{11}\)

Question 3.

Write five rational numbers which are smaller than 2.

Solution:

We can take 0, 2 because 0 is smaller than 2.

2 can be written as \(\frac{20}{10}\) and 0, as \(\frac{0}{10}\)

Thus we have \(\frac{19}{10}\), \(\frac{18}{12}\), \(\frac{17}{10}\), \(\frac{16}{10}\), \(\frac{15}{10}\) ……………. \(\frac{1}{10}\) between 2 and 0. You can take any five of these.

Question 4.

Find ten rational numbers between \(\frac{-2}{5}\) and \(\frac{1}{2}\).

Solution:

You can take any ten of these.

Question 5.

Find five rational numbers between:

(i) \(\frac{2}{3}\) and \(\frac{4}{5}\)

(ii) \(\frac{-3}{2}\) and \(\frac{5}{3}\)

(iii) \(\frac{1}{4}\) and \(\frac{1}{2}\)

Sol.

Second Method

We know, if a and b are two rational numbers, then

\(\frac{a+b}{2}\) is a rational number between a and b such that a < \(\frac{a+b}{2}\) < b.

Solution:

Find the mean of the given rational numbers

We now find another rational number between \(\frac{2}{3}\) and \(\frac{22}{30}\).

For this, we again find the mean of \(\frac{2}{3}\) and \(\frac{22}{30}\). That is

Question 6.

Write five rational numbers greater than -2.

Solution:

We can take -2,0 (0 is greater than -2).You can also take other number such that -2 < other number.

-2 = \(\frac{-20}{10}\)

0 = \(\frac{0}{10}\)

Thus we have \(\frac{-19}{10}\), \(\frac{-18}{10}\), \(\frac{-17}{10}\), \(\frac{-16}{10}\) …………………. \(\frac{0}{10}\)

Question 7.

Find ten rational numbers between \(\frac{3}{5}\) and \(\frac{3}{4}\).

Solution:

You can take any ten of these.