# HBSE 8th Class Maths Solutions Chapter 1 Rational Numbers Ex 1.2

Haryana State Board HBSE 8th Class Maths Solutions Chapter 1 Rational Numbers Ex 1.2 Textbook Exercise Questions and Answers.

## Haryana Board 8th Class Maths Solutions Chapter 1 Rational Numbers Exercise 1.2

Question 1.
Represent these numbers on the number line, (i) $$\frac{7}{4}$$ (ii) $$\frac{-5}{6}$$
Solution:
(i) To represent $$\frac{7}{4}$$, we make 7 marking of distance $$\frac{1}{4}$$ each on the right of zero and starting from 0. The seventh marking is $$\frac{7}{4}$$.

(ii) $$\frac{-5}{6}$$
To represent $$\frac{-5}{6}$$, the number line may be divided into six equal parts. We make 6 marking of distance $$\frac{1}{6}$$ each on the left of zero and starting from 0. The fifth marking is $$\frac{-5}{6}$$.

Question 2.
Represent $$\frac{-2}{11}$$, $$\frac{-5}{11}$$, $$\frac{-9}{11}$$ on the number line.
Solution:
To represent $$\frac{-2}{11}$$, $$\frac{-5}{11}$$, $$\frac{-9}{11}$$. The number line may be divided into eleven equal parts. We make 11 marking of distance $$\frac{1}{11}$$ each on the left of zero and starting from 0. The second fifth and ninth making are $$\frac{-2}{11}$$, $$\frac{-5}{11}$$, $$\frac{-9}{11}$$

Question 3.
Write five rational numbers which are smaller than 2.
Solution:
We can take 0, 2 because 0 is smaller than 2.
2 can be written as $$\frac{20}{10}$$ and 0, as $$\frac{0}{10}$$
Thus we have $$\frac{19}{10}$$, $$\frac{18}{12}$$, $$\frac{17}{10}$$, $$\frac{16}{10}$$, $$\frac{15}{10}$$ ……………. $$\frac{1}{10}$$ between 2 and 0. You can take any five of these.

Question 4.
Find ten rational numbers between $$\frac{-2}{5}$$ and $$\frac{1}{2}$$.
Solution:

You can take any ten of these.

Question 5.
Find five rational numbers between:
(i) $$\frac{2}{3}$$ and $$\frac{4}{5}$$
(ii) $$\frac{-3}{2}$$ and $$\frac{5}{3}$$
(iii) $$\frac{1}{4}$$ and $$\frac{1}{2}$$
Sol.

Second Method
We know, if a and b are two rational numbers, then
$$\frac{a+b}{2}$$ is a rational number between a and b such that a < $$\frac{a+b}{2}$$ < b.
Solution:
Find the mean of the given rational numbers

We now find another rational number between $$\frac{2}{3}$$ and $$\frac{22}{30}$$.
For this, we again find the mean of $$\frac{2}{3}$$ and $$\frac{22}{30}$$. That is

Question 6.
Write five rational numbers greater than -2.
Solution:
We can take -2,0 (0 is greater than -2).You can also take other number such that -2 < other number.
-2 = $$\frac{-20}{10}$$
0 = $$\frac{0}{10}$$
Thus we have $$\frac{-19}{10}$$, $$\frac{-18}{10}$$, $$\frac{-17}{10}$$, $$\frac{-16}{10}$$ …………………. $$\frac{0}{10}$$

Question 7.
Find ten rational numbers between $$\frac{3}{5}$$ and $$\frac{3}{4}$$.
Solution:

You can take any ten of these.