# HBSE 7th Class Maths Solutions Chapter 1 Integers Ex 1.2

Haryana State Board HBSE 7th Class Maths Solutions Chapter 1 Integers Ex 1.2 Textbook Exercise Questions and Answers.

## Haryana Board 7th Class Maths Solutions Chapter 1 Integers Exercise 1.2

Question 1.
Write pair of integers whose sum gives:
(a) A negative integer.
(b) Zero.
(c) An integer smaller than both the integers.
(d) An integer smaller than only one of the integers.
(e) An integer greater than both the integers.
Solution:
(a) – 3 + (- 3) = – 3 – 3 = – 6
(b) 3 + (-3) = 3 -3 = 0
(c) 3 + (- 2) = 3 – 2 = 1
(d) – 3 + (- 1) = – 3 – 1 = – 4
(e) 4 + 5 = 9

Question 2.
Write a pair of integers whose diffeences gives:
(a) A negative integer.
(b) Zero.
(c) An integer smaller than both the integers.
(d) An integer greater than only one of the integers.
(e) An integer greater than both the integers.
Solution:
(a) – 3 – (+ 3) = – 3 – 3 = – 6
(b) – 3 – (+ 3) = – 3 + 3 = – 0
(c) – 3 – (+ 2) = – 3 – 2 = – 5
(d) – 2 – (- 1) = – 2 + 1 = – 0
(e) – 3 – (- 4) = – 3 + 4 = 1

Question 3.
In a quiz team A scored – 40,10,0 and team B scored 10, 0, – 40 in three successive rounds. Which team scored more ? Can we say that we can add integers in any order ?
Solution:
Total score of A team = (- 40) + 10 + 0 = – 40 + 10 = – 30
Total score of B team = 10 + 0 + (- 40) = 10 – 40 = – 30
So, score of both team are equal.
Yes, we can add integers in any order.

Question 4.
Fill in the blanks to make the following statements true :
(i) (- 5) + (……………. ) = (- 8) + (……………. )
(ii) -53 + ……………. =-53
(iii) 17 + ……………. = 0
(iv) [13 + (- 12)] + (…………….) = ……………. + [(- 12) + (-7)]
(v) (- 4) + […………….+(-3)] = […………….+15] + …………….
Solution:
(i) (-5) +(-8) = (-8) +(-5)
(ii) -53 + 0 = -53
(iii) 17 + (— 17) = 0
(iv) [13 + (-12)] + (-7)
= 13 + [(- 12) +(-7)]
(v) (-4) + {15+(-3)} = { -4+15 } + (-3)