Haryana State Board HBSE 6th Class Maths Solutions Chapter 14 Practical Geometry Ex 14.5 Textbook Exercise Questions and Answers.
Haryana Board 6th Class Maths Solutions Chapter 14 Practical Geometry Exercise
14.5
Try These (Page 211) :
Question 1.
Can you now write the following numbers as decimals ?
| Hundreds | Tens | Ones | Tenths | ||
| (100) | (10) | (1) | (1/10) | ||
| (i) 5 | 3 | 8 | 1 | ||
| (ii) 2 | 7 | 3 | 4 | ||
| (iii) 3 | 5 | 4 | 6 | ||
Solution:
(i) 538.1,
(ii) 273.4,
(iii) 354.6.
Question 2.
Write the lengths of Ravi’s and Raju’s pencils in cm using decimals.
Solution:
Length of Ravi’s pencil
= 7 cm 5 mm = 7.5 cm.
Length of Raju’s pencil
= 8 cm 3 mm = 8.3 cm.
Question 3.
Make three more examples similar to the one given in question 1 and solve them.
Solution:
(i) Ram has rupees 40 and seventy-five paise and Shyam has rupees 70 and fifty paise. Express these amounts in decimal fractions.
(ii) The length of a wire is 6 metre and 30 cm. Write this length of wire in metres.
(iii) Pallavi and Ashu measured the lengths of their pencils. Pallavi’s pencil was 6 cm and 4 mm long and Ashu’s pencil was 5 cm 7 mm. Write the lengths of their pencils in cm.
Solution:
(i) Rs. 40 and seventy five paise
= Rs. 40.75
Rs. 70 and fifty paise
= Rs. 70.50
(ii) The length of the wire
= 6 metre and 30 cm = 6.30 m.
(iii) Length of Pallavi’s pencil
= 6 cm and 4 mm = 6.4 cm.
Length of Ashu’s pencil
= 5 cm and 7 mm = 5.7 cm.
Try These (Page 212):
Question.
Represent the following numbers on the number line :
(i) 0.6, (ii) 1.2, (Hi) 2.3.
Solution:
(i) We know that 0.6 is more than zero but less than one. There are 6 tenths in it. Divide the unit length between 0 and 1 into 10 equal parts and take 6 parts as shown below:
(ii) We know that 1.2 is more than one but less than two. There are 2 lengths in it. Divide the unit length between 1 and 2 into 10 the equal parts and take 2 parts as shown below :
(iii) We know that 1.2 is more than one but less than two. There are 2 lengths in it. Divide the unit length between 1 and 2 into 10 the equal parts and take 2 parts as shown below :
Try These (Page 213) :
Question.
Write \(\frac{3}{2}, \frac{4}{5}, \frac{8}{5}\) in decimal notation.
Solution:
Decimals as Fractions :
Write a decimal number 1.2 as a fraction.
Solution:
1.2 = 1.2 \(=\frac{10}{10}+\frac{2}{10}=\frac{10+2}{10}=\frac{12}{10}=\frac{6}{5}\)
Try These
Question 1.
David was measuring the length of his room. He found that the length of his room is 4 m and 25 cm. He wanted to write the length in metres. Can you help him.
Solution:
4 m and 25 cm = 4 + \(\frac{25}{100}\) = 4.25 m.
Question 2.
Fill in the blanks :
Ordinary fraction Decimal fraction
Solution:
(a) 0.50,
(b) 0.92.
Question 3.
Write the number in decimal fraction:
Solution:
The number is 2 + \(\frac{4}{10}+\frac{3}{100}\) = 2 + 0.4 + 0.03 = 2.43.
Try These (Page 224) :
Question.
Compare :
(i) 1.82 and 1.823
(ii) 5.7 and 4.9
(iii) 6.05 and 6.50
(iv) 3.15 and 3.18.
Solution:
Try These (Page 225):
(i) Write 2 rupees 5 paise and 2 rupees 50 paise in decimals.
(it) Write 20 rupees 7 paise and 21 rupees 75 paise in decimals.
Solution:
(i) We know that
100 paise = 1 Re
.’. 1 paise = \(\frac{1}{100}\) Re = 0.01 Re
.’. 5 paise = \(\frac{5}{100}\) Re = 0.05 Re
Hence, 2 rupees 5 paise 2.05 Rs.
and 50 paise = \(\frac{50}{100}\) = 0.5 Re
Hence, 2 rupees 50 paise = 2.50 Rs.
(ii) We know that
100 paise = 1 Re.
1 paise = \(\frac{1}{100}\) Re = 0.01 Re
7 paise = \(\frac{7}{100}\) = 0.07 Re
Hence, 20 rupees 7 paise = 20.07 Rs. 75
75 paise = \(\frac{75}{100}\) = 0.75 Re.
Hence, 21 rupees 75 paise = Rs. 21.75.
Try These (Page 226) :
(1) Can you write 4 mm in cm using decimals ?
(2) How will you write 7 cm 5 mm in cm using decimals ?
Solution:
(1) 4mm = \(\frac{4}{10}\) cm = 0.4 cm
(2) 7 cm 5 mm = 7 + [atex]\frac{5}{10}[/latex] = 7.5 cm.
Try These (Page 227):
Question.
(a) Can you write 456 g as kg using decimals ?
(b) How will you write 2 kg 9 g in kg using decimals ?
Solution:
(a) We know that
1000 g = 1 kg.
1 kg = \(\frac{1}{1000}\) kg = 0.001 kg
Hence, 456 g = \(\frac{456}{1000}\) = 0.456 kg.
(b) We know that
1000 g = 1 kg.
1 kg = \(\frac{1}{1000}\) kg = 0.001 kg
Hence 2 kg 9 g = 2 + \(\frac{9}{1000}\)
= 2 + 0.009
= 2.009 kg.
Try These (Page 229):
Find: (i) 0.29 + 0.36
(ii) 0.7 + 0.08
(iii) 1.54 + 1.80
(iv) 2.66 + 1.85.
Solution:
Try These {Page 232):
(i) Subtract 1.85 from 5.46
(ii) Subtract 5.25 from 8.28
(iii) Subtract 0.95 from 2.29
(iv) Subtract 2.25 from 5.68.
Solution:
