Haryana State Board HBSE 6th Class Maths Solutions Chapter 14 Practical Geometry Ex 14.5 Textbook Exercise Questions and Answers.

## Haryana Board 6th Class Maths Solutions Chapter 14 Practical Geometry Exercise

## 14.5

Try These (Page 211) :

Question 1.

Can you now write the following numbers as decimals ?

Hundreds | Tens | Ones | Tenths | ||

(100) | (10) | (1) | (1/10) | ||

(i) 5 | 3 | 8 | 1 | ||

(ii) 2 | 7 | 3 | 4 | ||

(iii) 3 | 5 | 4 | 6 |

Solution:

(i) 538.1,

(ii) 273.4,

(iii) 354.6.

Question 2.

Write the lengths of Ravi’s and Raju’s pencils in cm using decimals.

Solution:

Length of Ravi’s pencil

= 7 cm 5 mm = 7.5 cm.

Length of Raju’s pencil

= 8 cm 3 mm = 8.3 cm.

Question 3.

Make three more examples similar to the one given in question 1 and solve them.

Solution:

(i) Ram has rupees 40 and seventy-five paise and Shyam has rupees 70 and fifty paise. Express these amounts in decimal fractions.

(ii) The length of a wire is 6 metre and 30 cm. Write this length of wire in metres.

(iii) Pallavi and Ashu measured the lengths of their pencils. Pallavi’s pencil was 6 cm and 4 mm long and Ashu’s pencil was 5 cm 7 mm. Write the lengths of their pencils in cm.

Solution:

(i) Rs. 40 and seventy five paise

= Rs. 40.75

Rs. 70 and fifty paise

= Rs. 70.50

(ii) The length of the wire

= 6 metre and 30 cm = 6.30 m.

(iii) Length of Pallavi’s pencil

= 6 cm and 4 mm = 6.4 cm.

Length of Ashu’s pencil

= 5 cm and 7 mm = 5.7 cm.

Try These (Page 212):

Question.

Represent the following numbers on the number line :

(i) 0.6, (ii) 1.2, (Hi) 2.3.

Solution:

(i) We know that 0.6 is more than zero but less than one. There are 6 tenths in it. Divide the unit length between 0 and 1 into 10 equal parts and take 6 parts as shown below:

(ii) We know that 1.2 is more than one but less than two. There are 2 lengths in it. Divide the unit length between 1 and 2 into 10 the equal parts and take 2 parts as shown below :

(iii) We know that 1.2 is more than one but less than two. There are 2 lengths in it. Divide the unit length between 1 and 2 into 10 the equal parts and take 2 parts as shown below :

Try These (Page 213) :

Question.

Write \(\frac{3}{2}, \frac{4}{5}, \frac{8}{5}\) in decimal notation.

Solution:

Decimals as Fractions :

Write a decimal number 1.2 as a fraction.

Solution:

1.2 = 1.2 \(=\frac{10}{10}+\frac{2}{10}=\frac{10+2}{10}=\frac{12}{10}=\frac{6}{5}\)

Try These

Question 1.

David was measuring the length of his room. He found that the length of his room is 4 m and 25 cm. He wanted to write the length in metres. Can you help him.

Solution:

4 m and 25 cm = 4 + \(\frac{25}{100}\) = 4.25 m.

Question 2.

Fill in the blanks :

Ordinary fraction Decimal fraction

Solution:

(a) 0.50,

(b) 0.92.

Question 3.

Write the number in decimal fraction:

Solution:

The number is 2 + \(\frac{4}{10}+\frac{3}{100}\) = 2 + 0.4 + 0.03 = 2.43.

Try These (Page 224) :

Question.

Compare :

(i) 1.82 and 1.823

(ii) 5.7 and 4.9

(iii) 6.05 and 6.50

(iv) 3.15 and 3.18.

Solution:

Try These (Page 225):

(i) Write 2 rupees 5 paise and 2 rupees 50 paise in decimals.

(it) Write 20 rupees 7 paise and 21 rupees 75 paise in decimals.

Solution:

(i) We know that

100 paise = 1 Re

.’. 1 paise = \(\frac{1}{100}\) Re = 0.01 Re

.’. 5 paise = \(\frac{5}{100}\) Re = 0.05 Re

Hence, 2 rupees 5 paise 2.05 Rs.

and 50 paise = \(\frac{50}{100}\) = 0.5 Re

Hence, 2 rupees 50 paise = 2.50 Rs.

(ii) We know that

100 paise = 1 Re.

1 paise = \(\frac{1}{100}\) Re = 0.01 Re

7 paise = \(\frac{7}{100}\) = 0.07 Re

Hence, 20 rupees 7 paise = 20.07 Rs. 75

75 paise = \(\frac{75}{100}\) = 0.75 Re.

Hence, 21 rupees 75 paise = Rs. 21.75.

Try These (Page 226) :

(1) Can you write 4 mm in cm using decimals ?

(2) How will you write 7 cm 5 mm in cm using decimals ?

Solution:

(1) 4mm = \(\frac{4}{10}\) cm = 0.4 cm

(2) 7 cm 5 mm = 7 + [atex]\frac{5}{10}[/latex] = 7.5 cm.

Try These (Page 227):

Question.

(a) Can you write 456 g as kg using decimals ?

(b) How will you write 2 kg 9 g in kg using decimals ?

Solution:

(a) We know that

1000 g = 1 kg.

1 kg = \(\frac{1}{1000}\) kg = 0.001 kg

Hence, 456 g = \(\frac{456}{1000}\) = 0.456 kg.

(b) We know that

1000 g = 1 kg.

1 kg = \(\frac{1}{1000}\) kg = 0.001 kg

Hence 2 kg 9 g = 2 + \(\frac{9}{1000}\)

= 2 + 0.009

= 2.009 kg.

Try These (Page 229):

Find: (i) 0.29 + 0.36

(ii) 0.7 + 0.08

(iii) 1.54 + 1.80

(iv) 2.66 + 1.85.

Solution:

Try These {Page 232):

(i) Subtract 1.85 from 5.46

(ii) Subtract 5.25 from 8.28

(iii) Subtract 0.95 from 2.29

(iv) Subtract 2.25 from 5.68.

Solution: