HBSE 6th Class Maths Solutions Chapter 3 Playing With Numbers Ex 3.6

Haryana State Board HBSE 6th Class Maths Solutions Chapter 3 Playing With Numbers Ex 3.6 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 3 Playing With Numbers Exercise 3.6

Question 1.
Find the H.C.F of the following numbers:
(a) 18, 48
(b) 30, 42
(c) 18, 60
(d) 27, 63
(e) 36, 84
(f) 34, 102
(g) 70, 105, 175
(h) 91, 112, 49
(i) 18, 54, 81
(j) 12, 45, 75.
Solution:
(a)
HBSE 6th Class Maths Solutions Chapter 3 Playing With Numbers Ex 3.6 1
HBSE 6th Class Maths Solutions Chapter 3 Playing With Numbers Ex 3.6 2

HBSE 6th Class Maths Solutions Chapter 3 Playing With Numbers Ex 3.6

Question 2.
What is the H.C.F. of two consecutive :
(a) numbers ? .
(b) even numbers ?
(c) odd numbers ?
Solution:
(a) H.C.F. of two consecutive numbers is 1.
(b) H.C.F. of two consecutive even numbers is 2.
(c) H.C.F. of two consecutive odd numbers is 1.

HBSE 6th Class Maths Solutions Chapter 3 Playing With Numbers Ex 3.6

Question 3.
H.C.F. of co-prime numbers 4 and 15 was found as follows : Factorisation : 4 = 2×2 and 15 = 3 × 5, since there is no common prime factor, so H.C.F. of 4 and 15 is 0. Is the answer correct ? If not, what is the correct H.C.F. ?
Solution:
No, the correct H.C.F. is 1.

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