HBSE 6th Class Maths Solutions Chapter 11 Algebra Ex 11.3

Haryana State Board HBSE 6th Class Maths Solutions Chapter 11 Algebra Ex 11.3 Textbook Exercise Questions and Answers.

Haryana Board 6th Class Maths Solutions Chapter 11 Algebra Exercise 11.3

Question 1.
Make up as many expressions with numbers (no variables) as you can from three numbers 5, 7 and 8. Every number should be used not more than once. Use only addition, subtraction and multi-plication.
[Hint: Three possible expressions are 5 + (8 – 7), 5 – (8 – 7), 5 x 8 + 7 make the other expressions.]
Solution:
7 + (8 – 5), 7 – (8 – 5), 7 x 8 + 5, 7 x 8 – 5; 7 – (8 + 5) .
8 + (5 – 7), 8 – (5 – 7), 8 x 5 + 7, 8 x 5 – 7, 8 – (5 + 7) etc.

Question 2.
Which, out of the following, are expressions with numbers only ?
(a) y + 3
(b) 7 x 20 – 82
(c) 5 (21 – 7) + 7 x 2
(d) 5
(e) 3x
(f) 5 – 5n
(g) 7 x 20 – 5 x 10 – 45 + p.
Solution:
(c) and (d) are expressions with numbers only.

HBSE 6th Class Maths Solutions Chapter 11 Algebra Ex 11.3

Question 3.
Identify the operations (addition, subtraction, division, multiplication) in forming the following expressions and tell how the expressions have been formed :
(a) z +1, z-1, y + 17, y-17
(b) 17 y, ~, 5 z
(c) 2 y + 17, 2y – 17
(d) 7 m, – 7m +3,- 7m – 3
Solution:

Expression How formed
(a) z+ 1 1 is added to z
z – 1 1 is subtracted from 2
y + 17 17 is added to y
y- 17 17 is subtracted from y.
(b) 17 y y is multiplied by 17
y/17 y is divided by 17
5z 2 is multiplied by 5.
Expression How formed
(c) 2y+ 17 first y is multiplied by 2, then 17 is added to the product.
2y-17 first y is multiplied by 2, then 17 is subtracted from the product.
(d) 7 m m is multiplied by 7.
– 7m + 3 first m is multiplied by (-7), then 3 is added to the product.
– 7m – 3 first m is multiplied by (-7), then 3 is subtracted from the product.

Question 4.
Give expressions in the following cases :
(a) 7 added to p
(b) 7 subtracted from p
(c) p multiplied by 7
(d) p divided by 7
(e) 7 subtracted from – m
(f) – p multiplied by 5
(g) – p divided, by 5
(h) p multiplied by – 5.
Solution:
(a) 7 added to p : p + 7
(b) 7 subtracted from p : p—7
(c) p multiplied by 7 : 7p
(d) p divided by 7 : p ÷ 7 or \(\frac{p}{7}\)
(e) 7 subtracted from — m. : — m — 7
(J) —p multiplied by 5 : 5 x (—p) or —5p
(g) —p divided by 5 : (—p) ÷ 5 or –\(\frac{p}{5}\)
(h) p multiplied by —5 : p x (—5) or —5p.

Question 5.
Give expressions in the following cases :
(a) 11 added to 2 m
(b) 11 subtracted from 2 m
(c) 5 times y to which 3 is added
(d) 5 times y from which 3 is subtracted
(e) y is multiplied by (-8)
(f) y is multiplied by (-8) and then 5 is added to the result
(g) y is multiplied by 5 and the result is subtracted from 16
(h) y is multiplied by (-5) and the result is added to 16.
Solution:
(a) 2 m + 11
(b) 2m -11
(c) by + 3
(d) by – 3
(e) -8y
(f) -8y + 5
(g) 16 – 5y
(h) 16 – 5y.

HBSE 6th Class Maths Solutions Chapter 11 Algebra Ex 11.3

Question 6.
(a) Form expressions using ‘£’ and 4. Use not more than one number operation. Every expression must have ‘t’ in it.
(b) Form expressions using y, 2 and 7. Every expression must have y in it. Use only two number operations. These should be different.
Solution:
(a) t + 4, t – 4, 4t, \(\frac{t}{4}\)
(b) 2y + 7, 2y – 7, 7y + 2, 7y – 2.

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